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java如何将数字转换为字母(A=0、B=1、C=2等)

事实上我很抱歉代码不完整我想这可能更好。。我想要的是在算法完成后,我希望能够打印出数字输出,并将数字输出转换为字母。。很可能就像密码一样

public static void main(String args[])
{
    Scanner scanner = new Scanner(System.in);
    String ct;
    String k;
    int sum = 0;

    System.out.print("Enter Text: ");
    ct = scanner.nextLine();
    int arr1[] = new int[ct.length()];

    for(int j = 0; j < ct.length(); j++)
    {
        arr1[j] += ( (int)ct.charAt(j) - 97);
        System.out.println("Value of Text at["+j+"]: "+arr1[j]);
    }


    //user input key
    System.out.print("Enter random word: ");
    k = scanner.nextLine();

    for(int i = 0; i < k.length(); i++)
    {
        System.out.println( (int)k.charAt(i) - 97 );
        sum = sum + ( +(int)k.charAt(i) - 97 );
    }
    System.out.println("Sum of all letter in the random word: "+sum);
    for(int i = 0; i < ct.length(); i++)
    {
        System.out.print(arr1[i]+ " ");
        arr1[i] += sum;
        if(arr1[i] > 25)
        {
            arr1[i] -= 25;
            if(arr1[i] > 25)
            {
                arr1[i] -= 25;
            }
        }
    }
    System.out.println();
    for(int i = 0; i < ct.length(); i++)
    {
        System.out.print(arr1[i]+ " ");
    }

}

输出

Enter Text: kind
Value of Text at[0]: 10
Value of Text at[1]: 8
Value of Text at[2]: 13
Value of Text at[3]: 3
Enter random word: evil
4
21
8
11
Sum of all letter in the random word: 44
10 8 13 3 
4 2 7 22 

共 (2) 个答案

  1. # 1 楼答案

    如果你想做这样的事,请告诉我

    public class MainClass {
        public static void main(String[] args) {
        Scanner scanner=new Scanner(System.in);
        String s=scanner.nextLine();
        for(int i=0;i<s.length();i++){
            System.out.println("Value of the text at ["+i+"]: "+((int) s.charAt(i)-22)%25);
        }
    
      }
    }
    

    如果输入为:evil

    输出将是:

    Value of the text at [0]: 4

    Value of the text at [1]: 21

    Value of the text at [2]: 8

    Value of the text at [3]: 11

  2. # 2 楼答案

    您可以创建一个方法:

    public String getCharacterFromInt(int i) {
        return String.valueOf((char)(i + 'A'));
    }
    

    你可以调用这个方法:

    System.out.println("Value: "+getCharacterFromInt(0));
    

    使用0,返回一个 等等