java如何多线程更新由sql代码更新的数据库?
我制作了一个基本的CRUD spring启动应用程序,可以连接到Postgresql数据库。 我通过employeeDao中的sql代码访问数据库,该代码稍后在控制器中通过employeeService类调用。 我现在必须使用多线程方法更新数据库,但我不知道如何实现它
我做过任务执行者,但我没有;我真的不知道如何使用它
公共执行者任务执行者(){
final ThreadPoolTaskExecutor executor = new ThreadPoolTaskExecutor();
executor.setCorePoolSize(2);
executor.setMaxPoolSize(2);
executor.setQueueCapacity(50);
executor.setThreadNamePrefix("EmployeeThread-");
executor.initialize();
return executor;
}
这是我的员工建议:
public class EmployeeDaoImpl implements EmployeeDao{
public EmployeeDaoImpl(NamedParameterJdbcTemplate template) {
this.template = template;
}
NamedParameterJdbcTemplate template;
@Override
public List<Employee> findAll() {
return template.query("select * from employee", new EmployeeRowMapper());
}
@Override
public void insertEmployee(Employee emp) {
final String sql = "insert into employee(employeeId, employeeName ) values(:employeeId,:employeeName)";
KeyHolder holder = new GeneratedKeyHolder();
SqlParameterSource param = new MapSqlParameterSource()
.addValue("employeeId", emp.getEmployeeId())
.addValue("employeeName", emp.getEmployeeName());
template.update(sql,param, holder);
}
@Override
public void updateEmployee(Employee emp) {
final String sql = "update employee set employeeName=:employeeName where employeeId=:employeeId";
KeyHolder holder = new GeneratedKeyHolder();
SqlParameterSource param = new MapSqlParameterSource()
.addValue("employeeId", emp.getEmployeeId())
.addValue("employeeName", emp.getEmployeeName());
template.update(sql,param, holder);
}
@Override
public void executeUpdateEmployee(Employee emp) {
final String sql = "update employee set employeeName=:employeeName where employeeId=:employeeId";
Map<String,Object> map=new HashMap<String,Object>();
map.put("employeeId", emp.getEmployeeId());
map.put("employeeName", emp.getEmployeeName());
template.execute(sql,map,new PreparedStatementCallback<Object>() {
@Override
public Object doInPreparedStatement(PreparedStatement ps)
throws SQLException, DataAccessException {
return ps.executeUpdate();
}
});
}
@Override
public void deleteEmployee(Employee emp) {
final String sql = "delete from employee where employeeId=:employeeId";
Map<String,Object> map=new HashMap<String,Object>();
map.put("employeeId", emp.getEmployeeId());
template.execute(sql,map,new PreparedStatementCallback<Object>() {
@Override
public Object doInPreparedStatement(PreparedStatement ps)
throws SQLException, DataAccessException {
return ps.executeUpdate();
}
});
}
}
这是我的控制器
@RestController
@RequestMapping("/postgressApp")
public class ApplicationController {
@Resource
EmployeeService employeeService;
@GetMapping(value = "/employeeList")
public List<Employee> getEmployees() {
return employeeService.findAll();
}
@PostMapping(value = "/createEmp")
public void createEmployee(@RequestBody Employee emp) {
employeeService.insertEmployee(emp);
}
@PutMapping(value = "/updateEmp")
public void updateEmployee(@RequestBody Employee emp) {
employeeService.updateEmployee(emp);
}
@PutMapping(value = "/executeUpdateEmp")
public void executeUpdateEmployee(@RequestBody Employee emp) {
employeeService.executeUpdateEmployee(emp);
}
@DeleteMapping(value = "/deleteEmpById")
public void deleteEmployee(@RequestBody Employee emp) {
employeeService.deleteEmployee(emp);
}
}
我应该通过另一种方法(如Crud存储库)更改代码以更新数据库吗
# 1 楼答案
通常情况下,对于实时应用程序,来自用户的httprequest可以在不同的线程中到达。因此,应用程序控制器将从多个线程中调用。你自己不需要做太多关于多线程的事情
为了模拟这种情况,可以使用executor服务从Runnable调用各种ApplicationController方法。为每个操作向执行者提交一个runnable
但是,您必须小心,业务逻辑允许这种操作顺序。例如,您不能在创建员工之前更新他/她。同样,删除员工后,您不能更新他/她
或者,您可以通过使每个runnable只对一名员工进行操作,并按顺序执行一系列操作,从而使其更加有序
要使用executor服务,您可能需要阅读有关submitTask、Shutdownow和awaitTermination的内容:https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/ExecutorService.html
更快的介绍:http://tutorials.jenkov.com/java-util-concurrent/executorservice.html