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使用BufferedReader处理double时的java NumberFormatException

我在尝试将字符串数组中的字符串转换为双精度字符串时遇到问题

public class ImportFruitAndVegatables {
    List<Product> productList = new ArrayList<>();

    public List<Product> fillListWithProducts(){
        String filePath = "src/Resources/FruitAndVegetablesList.csv";
        String splitCsvBy = ",";

        try {
            BufferedReader bufferedReader = new BufferedReader(new FileReader(filePath));
            String line = "";
            line = bufferedReader.readLine(); //Reads the first line, without doing anything with it.
            System.out.println("try");
            while ((line = bufferedReader.readLine()) != null){
                String [] splitArray = line.split(splitCsvBy);
                System.out.println("while");
                System.out.println(splitArray[0]);
                System.out.println(Integer.parseInt(splitArray[1]));
                System.out.println(Double.parseDouble(splitArray[2]));
                Product product = new Product(splitArray[0],Double.parseDouble(splitArray[1]),Integer.parseInt(splitArray[2]));
                productList.add(product);
            }

        } catch (FileNotFoundException e) {
            System.out.println("The file was not found ");
            e.printStackTrace();
        } catch (IOException e) {
            System.out.println(); //TODO: print why the IOException occurred.
            e.printStackTrace();
        }

return productList;
    }
}

这是我得到的解释:

Exception in thread "main" java.lang.NumberFormatException: For input string: "2.5"
    at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:68)
    at java.base/java.lang.Integer.parseInt(Integer.java:652)
    at java.base/java.lang.Integer.parseInt(Integer.java:770)
    at ImportData.ImportFruitAndVegatables.fillListWithProducts(ImportFruitAndVegatables.java:28)
    at Controllers.MainController.runProgram(MainController.java:12)
    at Main.main(Main.java:8)

我的csv看起来像这样:

产品、价格、条形码

苹果,2.51159

橙色,2.51606

芒果,121603

梨,2.51148

问题是,它在Integer上完全可以正常工作。parseInt() 我试过用逗号代替句号,但也没用。我希望你能帮助我!:)

我的产品类构造函数如下所示:

公共产品(字符串名称、双倍价格、整数条形码)

enter image description here


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