?: 在Java中：如何更合理地组合res和resString？

Question

我希望输出（double res和String resString的混合）被分配一个变量

import java.util.Scanner;
public class Lab3Task02_08 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("х = ");
        int x = in.nextInt();
        System.out.print("y = ");
        int y = in.nextInt();
        double arithm = (x+y)/2;
        double geom = Math.sqrt(Math.abs(x*y));
        
        //////////////////////////////////////////////////////////////
        double res = x>y? arithm:geom;
        String resString = x>y? "Arithm.average = ":"Geom.average = ";
        //////////////////////////////////////////////////////////////

        System.out.print(resString + res);
        in.close();
    }
}

Answer 1

如果我理解这个问题，这就是你想要的吗

import java.util.Scanner;
public class Lab3Task02_08 {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        System.out.print("х = ");
        int x = in.nextInt();
        System.out.print("y = ");
        int y = in.nextInt();
        double arithm = (x+y)/2;
        double geom = Math.sqrt(Math.abs(x*y));
        
        //////////////////////////////////////////////////////////////
        double res = x>y? arithm:geom;
        String resString = x>y? "Arithm.average = ":"Geom.average = ";
        //////////////////////////////////////////////////////////////
        String combinedRes = resString + res;
        System.out.print(combinedRes);
        in.close();
    }
}

Answer 2

据我所知，您希望根据相同的条件输出两个不同的值。其中一个选项是，它可以通过String.format()、Double.compare()和x ? y : x完成

public static void main(String... args) throws ParseException {
    Scanner scan = new Scanner(System.in);

    System.out.print("х = ");
    int x = scan.nextInt();

    System.out.print("y = ");
    int y = scan.nextInt();

    double arithmetic = (x + y) / 2.;
    double geometric = Math.sqrt(Math.abs(x * y));
    int res = Double.compare(arithmetic, geometric);

    System.out.format(Locale.ENGLISH, "%s average = %.2f\n",
            res > 0 ? "Arithmetic" : "Geometric",
            res > 0 ? arithmetic : geometric);
}

输出：

х = 3
y = 5
Arithmetic average = 4.00

х = -4
y = 3
Geometric average = 3.46