java如何在包含映射的ArrayList上循环？

Question

目前，我正在使用rest assured访问端点，然后通过ArrayList和HashMap存储任何JSON数据匹配项

我可以看到我收到了一个响应，但是当ArrayList包含一个内部HashMap时，我该如何循环它呢

从下面的JSON数据可以看出，我希望输出存储在ArrayList中的所有值/匹配项

我的代码：

public void apiTest() {
    String position = "Attacker";
    String role = "PLAYER";

    Response response = given()
            .spec(footballCompetitions_requestSpecification)
            .when().get(EndPoint.TEAMS + EndPoint.SQUAD);

    ArrayList<Map<String, ?>> allPlayers = response.path
            ("squad.findAll { it.role == '%s' }.findAll  { it.position == '%s' }", position, role);

JSON数据示例：

 {
      "id": 66,
      "area": {
        "id": 2072,
        "name": "England"
      },
      "activeCompetitions": [
        {
          "id": 2021,
          "area": {
            "id": 2072,
            "name": "England"
          },
          "name": "Premier League",
          "code": "PL",
          "plan": "TIER_ONE",
          "lastUpdated": "2019-01-03T23:39:45Z"
        },
        {
          "id": 2001,
          "area": {
            "id": 2077,
            "name": "Europe"
          },
          "name": "UEFA Champions League",
          "code": "CL",
          "plan": "TIER_ONE",
          "lastUpdated": "2018-12-13T18:55:02Z"
        }
      ],
      "name": "Manchester United FC",
      "shortName": "Man United",
      "tla": "MNU",
      "crestUrl": "http://upload.wikimedia.org/wikipedia/de/d/da/Manchester_United_FC.svg",
      "address": "Sir Matt Busby Way Manchester M16 0RA",
      "phone": "+44 (0161) 8688000",
      "website": "http://www.manutd.com",
      "email": "enquiries@manutd.co.uk",
      "founded": 1878,
      "clubColors": "Red / White",
      "venue": "Old Trafford",
      "squad": [
        {
          "id": 3188,
          "name": "David De Gea",
          "position": "Goalkeeper",
          "dateOfBirth": "1990-11-07T00:00:00Z",
          "countryOfBirth": "Spain",
          "nationality": "Spain",
          "shirtNumber": 1,
          "role": "PLAYER"
        },
        {
          "id": 3331,
          "name": "Marcus Rashford",
          "position": "Attacker",
          "dateOfBirth": "1997-10-31T00:00:00Z",
          "countryOfBirth": "England",
          "nationality": "England",
          "shirtNumber": 10,
          "role": "PLAYER"
        },
        {
          "id": 3372,
          "name": "Anthony Martial",
          "position": "Attacker",
          "dateOfBirth": "1995-12-05T00:00:00Z",
          "countryOfBirth": "France",
          "nationality": "France",
          "shirtNumber": 11,
          "role": "PLAYER"
        },
        {
          "id": 3662,
          "name": "Romelu Lukaku",
          "position": "Attacker",
          "dateOfBirth": "1993-05-13T00:00:00Z",
          "countryOfBirth": "Belgium",
          "nationality": "Belgium",
          "shirtNumber": 9,
          "role": "PLAYER"
        },

Answer 1

如果您使用的是Java 8或更高版本，那么只需先在List上迭代，然后在Map上使用lambda表达式进行嵌套迭代：

public static void main(String[] args) {
    List<Map<String, ?>> jsonList = new ArrayList<>();

    Map<String, String> mapOne = new HashMap<String, String>();

    mapOne.put("id", String.valueOf(66));
    mapOne.put("area", "Some Area");

    jsonList.add(mapOne);

    jsonList.forEach(map -> {
        map.forEach((key, value) -> {
            System.out.println(key + ": " + value);
        });
    });
}

你需要注意的是String的value表示，因为它在你的代码中是Map<String, ?>，在我的例子中是Map<String, String>，如果你直接使用上面例子的System.out.println(key + ": " + value);，可能会导致什么问题