基于用户输入的max和min生成java中的随机数

Question

我在尝试用用户定义的max和min生成一组radom数字时遇到了一点麻烦，我对编程是新手，对我的代码感到有点迷茫

int upperRange;
int lowerRange;
Random random = new Random(int)(Math.random()*(upperRange - (lowerRange-1)))+lowerRange;

Scanner keyboard = new Scanner(System.in);


{

System.out.println("Enter upper limit number ");
upperRange = keyboard.nextInt();
System.out.println("Enter lower limit number");
lowerRange = keyboard.nextInt();

任何帮助都将不胜感激

Answer 1

其中r是Random类的实例，x和y是正整数

r.nextInt(y - x) + x

你应该做你想做的。它将为您提供一个范围为x（包含）到y（独占）的整数

Answer 2

试试这个：

public class TestRandomBounds {

    public static void main(String[] args) {

        int upperBound = 100;
        int lowerBound = 50;

        Random random = new Random();
        System.out.println(lowerBound + random.nextInt(upperBound - lowerBound));

     }
}

一旦定义了随机边界，您只需要生成一个将驻留在这些边界内的随机数

Answer 3

您的代码可以这样编写：

import java.util.*;

public class RandGuess
{
    public static void main ( String[] args )
    {
        int upperRange;
        int lowerRange;
        Random random;
        int randomFromUserLimits;

        Scanner keyboard = new Scanner(System.in);

        System.out.print("Enter upper limit number: ");
        upperRange = keyboard.nextInt();
        System.out.print("Enter lower limit number: ");
        lowerRange = keyboard.nextInt();
        random = new Random();
        randomFromUserLimits = random.nextInt(upperRange-lowerRange) + lowerRange;
        System.out.println("A random number between " + lowerRange + " and " + upperRange + " = " + randomFromUserLimits);
    }

}