使用单词和符号进行正则表达式Java拆分

Question

我有一个类似String str = "void Write(int *p,int a)"的字符串，我想得到函数名“str”和参数名“*p”，“a”。然而，我不知道有多少参数

我已经为regex写了"int\\s+|void\\s+|string\\s+|float\\s+|double\\s+|char\\s+\\(,\\)"

第一部分=Write(第二部分=*p,第三部分=a)

regex \\(,\\)的最后一部分用于删除分号和括号。但正如你所见，它失败了。我必须使用第二次拆分还是有其他方法

Answer 1

这将是一个两步的过程

步骤1：提取函数名和所有参数

步骤2：从所有参数列表中提取每个参数名称

第一步：

让我们将这个正则表达式^\S+\s+([^(]+)\(([^)]+)*应用于这个字符串void Write(int *p,int a, int b, str *v)这个测试字符串

^         # start of string
\S+       # one or more occurence of any non space charactcers
          # matches `void`
\s+       # one or more occurence of a space character
          # matches the space after `void`
([^(]+)   # all characters until opening parenthesis
          # matches `Write` and capture it
\(        # literally matches opening parenthesis
([^)]+)   # matches all characters till closing parenthesis is encountered
          # matches arguments signature i.e. `int *p,int a, int b, str *v`
*         # matches zero or more occurrence of last capturing group
          # last capturing group is string between the parenthesis
          # so this star handle the corner case when the argument list is empty

更多详细信息：https://regex101.com/r/0m1vs9/2

第二步

现在对参数列表（int *p,int a, int b, str *v）应用这个带有全局修饰符的正则表达式\s*\S+\s+([^,]+),?

该模式匹配逗号之间的文本，以便解释假设相同的模式

\s*      # matches zero or more occurrences of a space character
         # this will match any spaces after comma e.g. `int b,<space> str`
\S+      # one or more occurrence of non space character
         # matches argument type, i.e. `int`
\s+      # one or more occurrence of space characters
         # matches the space between argument name and type, e.g. `int<space>b`
([^,]+)  # capture all characters till comma
         # this matches the actual argument name
         # and also matches any spaces after it
,?       # zero or one occurrence of a comma
         # this ensures that the argument name is immediately followed by a comma
         # this also handles the case for the last argument which doesn't have any comma after it

更多详细信息：https://regex101.com/r/9ju60l/1

希望有帮助