java如何进行lastIndexOf与indexOf的比较?
对于我的java程序,我使用的是SingleLinkedList。下面是我测试的indexOf代码,它运行正常。我的问题是如何将indexOf更改为lastIndexOf。我有点搞不清楚它是怎么工作的,怎么做的
/**
* Returns the index of the first occurrence of the specified element in this list, or -1 if this list
* does not contain the element. More formally, returns the lowest index i such that
* (o==null ? get(i)==null : o.equals(get(i))), or -1 if there is no such index.
* @param item
* @return the index of the first occurrence of the specified element in this list,
* or -1 if this list does not contain the element
*/
public int indexOf(E item) {
Node<E> temp = head;
for(int i=0; i < size; i++){
if(temp.data.equals(item))
return i;
temp = temp.next;
}
return -1;
}
以下是lastIndexOf的java文档和标题:
/**
* Returns the index of the last occurrence of the specified element in this list,
* or -1 if this list does not contain the element. More formally, returns the highest
* index i such that (o==null ? get(i)==null : o.equals(get(i))), or -1 if there is no such index.
* @param item
* @return the index of the last occurrence of the specified element in this list,
* or -1 if this list does not contain the element
*/
public int lastIndexOf(E item) {
// TODO Auto-generated method stub
return 0;
}
# 1 楼答案
只需使用一个变量存储找到的最大索引,然后返回: