java试图在安卓中传递参数

Question

因此，我有两个文件（MainActivity.java和HomeFragment.java），我试图将名为displayPromptForEnablingGPS的public static void从HomeFragment传递到MainActivity。这是密码

HomeFragment.java（我试图传递的代码）

public static void displayPromptForEnablingGPS(
        final Activity activity)
{
    final AlertDialog.Builder builder =
            new AlertDialog.Builder(activity);
    final String action = Settings.ACTION_LOCATION_SOURCE_SETTINGS;
    final String message = "Enable either GPS or any other location"
            + " service to find current location.  Click OK to go to"
            + " location services settings to let you do so.";


    builder.setMessage(message)
            .setPositiveButton("OK",
                    new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface d, int id) {
                            activity.startActivity(new Intent(action));
                            d.dismiss();
                        }
                    })
            .setNegativeButton("Cancel",
                    new DialogInterface.OnClickListener() {
                        public void onClick(DialogInterface d, int id) {
                            d.cancel();
                        }
                    });
    builder.create().show();
}

MainActivity.java（我怎么称呼它）

public void showMainView() {
   HomeFragment.displayPromptForEnablingGPS();
}

但我有个错误

"HomeFragment.displayPromptForEnablingGPS();" is invalid

Answer 1

要调用的方法需要一个参数，但不能传递它

public static void displayPromptForEnablingGPS(
    final Activity activity)

MainActivity中的方法应该如下所示：

public void showMainView() {
   HomeFragment.displayPromptForEnablingGPS(this);
}