java四位数字程序:分组数字
我创建了一个程序,可以让你输入四个必须有特定要求的数字:
-必须是4或6的倍数
-如果大于500,则必须是10的倍数
该程序获取四个数字,并给出它们的总和、平均值,显示四个数字中最小的,最后是四个数字中最大的
现在我想尝试显示每个数字所属的组。如果你想知道:
如果数字在0到99之间,则将其分组
如果数字在100到999之间,则将数百人分组
如果数字在1000到999999之间,则将其分组为数千人
如果数字大于999999,则将其他人分组
我的问题是我不知道应该把它们放在我的程序中的什么地方(如下)
import java.util.Scanner;
public class FourNumbersProgram {
private static int readNumber(String message, Scanner in) {
System.out.println("Enter a numbers divislbe by 4 or 6. No negatives.");
System.out.println("**If greater than 500: must be multiple of 10");
System.out.print(message);
while (!in.hasNextInt()) {
in.next();
System.out.println("Sorry, couldn't understand you!");
System.out.print(message);
}
int a = in.nextInt();
return a;
}
private static int readNumberToMatchCondition(String message, Scanner in) {
int number = 0;
do {
number = readNumber(message, in);
if (number < 500) {
if (number % 4 != 0 && number % 6 != 0) {
System.out.println(number + " not divisible by 4 or 6");
} else {
return number;
}
} else {
if (number % 4 != 0 && number % 6 != 0) {
System.out.println(number + " not divisible by 4 or 6");
} else if (number % 10 != 0) {
System.out.println(number + " is greater than 500 and not divisible by 10");
} else {
return number;
}
}
} while (true);
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int randomNumber1 = readNumberToMatchCondition("Enter first number:", in);
int randomNumber2 = readNumberToMatchCondition("Enter second number:", in);
int randomNumber3 = readNumberToMatchCondition("Enter third number:", in);
int randomNumber4 = readNumberToMatchCondition("Enter fourth number:", in);
int sum; // sum of number1, number2, number3, and number4
int avg; // average of number1, number2, number3, and number4
int largest; // largest number of the four integers
int smallest; // smallest number of the four integers
sum = (randomNumber1 + randomNumber2 + randomNumber3 + randomNumber4);
avg = ((sum) / 4);
smallest = randomNumber1;
smallest = (randomNumber2 < smallest) ? randomNumber2 : smallest;
smallest = (randomNumber3 < smallest) ? randomNumber3 : smallest;
smallest = (randomNumber4 < smallest) ? randomNumber3 : smallest;
largest = randomNumber1;
largest = (randomNumber2 > largest) ? randomNumber2 :largest;
largest = (randomNumber3 > largest) ? randomNumber3 :largest;
largest = (randomNumber4 > largest) ? randomNumber4 :largest;
System.out.println();
System.out.println("First number entered: " + randomNumber1); //prints first number entered
System.out.println("Second number entered: " + randomNumber2); //prints second number entered
System.out.println("Third number entered: " + randomNumber3); //prints third number entered
System.out.println("Fourth number entered: " + randomNumber4); //prints fourth number entered
System.out.println();
System.out.println("The sum is: " + sum); //prints sum of four numbers
System.out.println("The average is: " + avg); //prints average of four numbers
System.out.println("The smallest number is: " + smallest); //prints smallest of the four numbers
System.out.println("The largest number is: " + largest); //prints largest of the four numbers
System.out.println();
}
}
这是我的代码副本:
我的教授给了我一个分组项目的例子(如下)
import java.util.Scanner;
public class Prog2 {
public static void main(String[] args){
Scanner in = new Scanner(System.in);// read a number
System.out.println("Enter a number: ");
int number = in.nextInt();
if (number < 0) {
System.out.println("Error: Sorry, no negative numbers allowed.");
System.exit(0);
}
int grp1 = (number / 100) + 1;
int grp2 = (number / 1000) + 1;
int grp3 = (number / 1000000) + 1;
switch (grp1){
case 1: // Group Tens
System.out.println(number + " belongs to Group Tens");
break;
default:
switch (grp2) {
case 1:// Group Hundreds
System.out.println(number + " belongs to Group Hundreds");
break;
default:
switch (grp3) {
case 1:// Group Thousands
System.out.println(number + " belongs to Group Thousands");
break;
default:// Group Others
System.out.println(number + " belongs to Group Others");
}
}
}
in.close();
}
}
这是他的密码副本:
我知道他的程序要求用户输入一个号码,然后程序将其分组。我想知道如何在我的程序中加入这样的内容。我很困惑,因为我有四个必须分组的数字,我不确定我是否必须为我所有的四个数字(随机数1,随机数2,随机数3,随机数4)重复类似于我教授程序的东西
请不要放置完整的已更正代码!我想自己修好并学习
# 1 楼答案
你的教授课程将适用于你所有的数字。只需调用该方法4次。每个数字一次。你需要做的是自己把他的代码放到一个方法中。(记住,如果他把它作为指导给你,那么他可能会希望你自己尝试编写逻辑)
假设你把他的代码放在一个方法中,看起来像:
然后,接下来,您需要做的就是将加载的每个值传递到该方法中。例如:
displayNumberGroup(randomNumber1);
。这将计算该数字的分组。我将把这件事交给你来解释,因为你要求不要被人用勺子舀答案(这是非常值得称赞的!)# 2 楼答案
你不需要做randomNumber1,randomNumber2,等等,你可以把它们做成一个数组。通过这样做,你可以在给定的开关上放置一个for循环,并运行它4次,这样你所有的数字都有组。如果你需要我用一个简单的例子来解释其中的任何部分,我会的,但我知道你想自己做这件事,所以如果你有任何问题,请告诉我