java无法获得正确的温度转换输出
好的,所以我的程序编译和运行得很好,但目的是在摄氏度、华氏度和开尔文之间转换,当程序与客户端一起运行时,它显示正确的单位(F、C、K),但所有温度的值都是50。我该怎么解决这个问题
public class Temperature
{
private double value;
private String scale;
public Temperature() // default constructor
{
this.value = 0;
this.scale = "C";
}
public Temperature(double value, String scale)
{
this.value = value;
this.scale = scale;
}
public double getValue()
{
return this.value;
}
public String getScale()
{
return this.scale;
}
public double getCelsius()
{
if (scale.equalsIgnoreCase ("C"))
{
return this.value;
}
else if (scale.equalsIgnoreCase("F"))
{
double faren = ((this.value - 32) * (5/9));
return faren;
}
else
{
double kelvin = (this.value - 273.15);
return kelvin;
}
} // end getCelcius
public double getFaren()
{
if (scale.equalsIgnoreCase ("F"))
{
return this.value;
}
else if (scale.equalsIgnoreCase("C"))
{
double celsius = ((this.value * 1.8) + 32);
return celsius;
}
else
{
double kelvin = ((this.value * 1.8) - 459.67);
return kelvin;
}
} // ene getFaren
public double getKelvin()
{
if (scale.equalsIgnoreCase("K"))
{
return this.value;
}
else if (scale.equalsIgnoreCase("C"))
{
double celsius = (this.value + 273.15);
return celsius;
}
else
{
double faren = ((this.value + 459.67) * (5/9));
return faren;
}
} // end getKelvin
public void setTemperature(Temperature t)
{
this.value = t.value;
}
public void setType(double degree, String measure)
{
this.value = degree;
this.scale = measure;
}
public void setValue(double degree)
{
this.value = degree;
}
public void setScale(String measure)
{
this.scale = measure;
}
public double convertToCelsius()
{
this.scale = "C";
return this.value = getCelsius();
}
public double convertToFaren()
{
this.scale = "F";
return this.value = getFaren();
}
public double convertToKelvin()
{
this.scale = "K";
return this.value = getKelvin();
}
public Temperature clone()
{
return new Temperature(this.value, this.scale);
}
public boolean equals()
{
return this.value == this.value && this.scale == this.scale;
}
public String toString()
{
String temps = ("The temperature is " + this.value + "(" + this.scale + ")");
return temps;
}
}
# 1 楼答案
你应该改变
到
其他天平也是如此。 首先设置
scale
,这样对象就可以看到scale
是相同的,而不进行转换