java循环重复一个tic tac toe游戏
我写了一段代码,从头到尾都在玩tic-tac-toe。游戏结束后,我需要询问用户是否想重复游戏(是/否),然后重复,直到用户输入否。我不确定在哪里实现循环或如何实现循环,因此非常感谢帮助。代码如下:
import java.util.Scanner;
public class bb2 {
static char place1 = ' ';
static char place2 = ' ';
static char place3 = ' ';
static char place4 = ' ';
static char place5 = ' ';
static char place6 = ' ';
static char place7 = ' ';
static char place8 = ' ';
static char place9 = ' ';
static Scanner input;
public static void main(String[] args) {
input = new Scanner(System.in);
while (true) { // TTT 4 forever!
printGameBoard();
userInput();
if (checkForWin('X')) {
System.out.println("Congrats, you won!");
break;
}
if (checkForStale()) {
printGameBoard();
System.out.println("Tie!");
break;
}
computerTurn();
if (checkForWin('O')) {
System.out.println("All hail the future overlords!");
break;
}
if (checkForStale()) {
System.out.println("Tie!");
break;
}
}
}
static void printGameBoard() {
System.out.println(place1 + " | " + place2 + " | " + place3 + "\n---------");
System.out.println(place4 + " | " + place5 + " | " + place6 + "\n---------");
System.out.println(place7 + " | " + place8 + " | " + place9 + "\n");
}
static void userInput() {
System.out.print("Please enter the board number:");
int place = input.nextInt();
// Note to self: check user input for sanity here!
if (checkForSanity(place)) {
placeOnBoard(place, 'X');
System.out.println("Ok...");
printGameBoard();
} else {
System.out.println("Wrong move!");
}
}
static void computerTurn() {
boolean placed = false;
while (!placed) {
// Randomly choose a place
int place = (int) (1 + (Math.random() * 8));
// Check if sane
if (checkForSanity(place)) {
placeOnBoard(place, 'O');
placed = true;
}
}
printGameBoard();
}
static boolean checkForWin(char piece) {
if ((place1 == piece) && (place2 == piece) && (place3 == piece))
return true;
if ((place4 == piece) && (place5 == piece) && (place6 == piece))
return true;
if ((place7 == piece) && (place8 == piece) && (place9 == piece))
return true;
if ((place1 == piece) && (place4 == piece) && (place7 == piece))
return true;
if ((place2 == piece) && (place5 == piece) && (place8 == piece))
return true;
if ((place3 == piece) && (place6 == piece) && (place9 == piece))
return true;
if ((place1 == piece) && (place5 == piece) && (place9 == piece))
return true;
if ((place3 == piece) && (place5 == piece) && (place7 == piece))
return true;
return false;
}
static boolean checkForStale() {
if ((place1 != ' ') && (place2 != ' ') && (place3 != ' ')
&& (place4 != ' ') && (place5 != ' ') && (place6 != ' ')
&& (place7 != ' ') && (place8 != ' ') && (place9 != ' '))
return true;
return false;
}
static void placeOnBoard(int place, char piece) {
if (place == 1)
place1 = piece;
else if (place == 2)
place2 = piece;
else if (place == 3)
place3 = piece;
else if (place == 4)
place4 = piece;
else if (place == 5)
place5 = piece;
else if (place == 6)
place6 = piece;
else if (place == 7)
place7 = piece;
else if (place == 8)
place8 = piece;
else if (place == 9)
place9 = piece;
}
static boolean checkForSanity(int place) {
boolean sane = false;
if ((place == 1) && (place1 == ' '))
sane = true;
else if ((place == 2) && (place2 == ' '))
sane = true;
else if ((place == 3) && (place3 == ' '))
sane = true;
else if ((place == 4) && (place4 == ' '))
sane = true;
else if ((place == 5) && (place5 == ' '))
sane = true;
else if ((place == 6) && (place6 == ' '))
sane = true;
else if ((place == 7) && (place7 == ' '))
sane = true;
else if ((place == 8) && (place8 == ' '))
sane = true;
else if ((place == 9) && (place9 == ' '))
sane = true;
return sane;
}
static boolean checkForSanity(int row, int col) {
return true;
}
}
# 1 楼答案
很多事情都错了(x)
首先,如果你在游戏板上使用char[]会更好。(而不是“地点1,地点2,…) 所以你可以使用你的“boolean checkForSanity(int row,int col)”,所有的代码都会非常漂亮
然后,你使用“while(true)”,但不要在棋盘已满或有人赢了时重置棋盘。。。所以我相信你会得到一个无限的“向未来的霸主致敬!”
不管怎样,我认为你的TTT有效,这是最主要的:) 现在你必须把你的“while(true){//playing}”放在另一个while中,就像这样:
# 2 楼答案
首先,我建议为所有位置选择一个字符数组,而不是单个变量。这样,您就可以使用循环,而不是在if语句中编写一百万个条件语句。而且
while(true)
循环将永远运行,而不会清除网格。我建议创建一个方法,当没有任何一个位置的值为' '
或有人获胜时,检查并返回true,并在while循环中实现该方法要回答您最初的问题,只需创建一个清除网格的方法,并在主函数开始时实现它,然后将整个过程固定在一个while循环中
# 3 楼答案
尝试将现有
main
方法的全部内容移动到一个新方法,或者将其称为类似playOnce
的方法,然后用循环编写一个新的主方法,并提示用户重试