java如何在安卓中将JSONObject转换为字符串数组或ArrayList<String>

Question

我将获取JSONObject的值，并将其放入字符串数组或ArrayList中。问题是我有一个JSONObject而不是JSONArray，而且我无法更改Web服务。 这是我的JSONObject：

{“THR”：“THR”， “MHD”：“MHD”， “KIH”：“کیش”， “IFN”：“IFN”， “SYZ”：“SYZ”， “TBZ”：“TBZ”， “ABD”：“ABD”

这是我的代码：

    ProgressBar progressbar = (ProgressBar) findViewById(R.id.progressbar);
    RequestQueue queue = Volley.newRequestQueue(getApplicationContext());

    progressbar.setVisibility(View.VISIBLE);
    StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Toast.makeText(getApplicationContext(), "Response", Toast.LENGTH_SHORT).show();
            progressbar.setVisibility(View.GONE);

            try {
                JSONArray array = new JSONArray(response);
                Toast.makeText(getApplicationContext(), "Try", Toast.LENGTH_LONG).show();
            } catch (JSONException e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), "Catch", Toast.LENGTH_LONG).show();
            }

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_SHORT).show();
            progressbar.setVisibility(View.GONE);
        }
    });

    queue.add(stringRequest);

当我调试代码时，它会被捕获！！！ 无论如何，它不会去尝试

我想要这样的东西：

String[] strArray = {"تهران","مشهد","کیش","اصفهان","شیراز","تبریز","آبادان"};

我怎么才能拿到

Answer 1

添加了对代码的更改

ProgressBar progressbar = (ProgressBar) findViewById(R.id.progressbar);
    RequestQueue queue = Volley.newRequestQueue(getApplicationContext());
    ArrayList<String> answersStringArray= new ArrayList<String>(); // define string array

progressbar.setVisibility(View.VISIBLE);
    StringRequest stringRequest = new StringRequest(Request.Method.GET, url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            Toast.makeText(getApplicationContext(), "Response", Toast.LENGTH_SHORT).show();
            progressbar.setVisibility(View.GONE);

            try {
                JJSONObject jsonObject = new JSONObject(response); //cast responce to jsonObject
                Iterator<?> keys = jsonObject.keys(); // get the keys of the jsonObject
                while( keys.hasNext() ) {//iterrate over them
                    String key = (String)keys.next();
                    answersStringArray.add(jsonObject.optString(key));}// add the string to our array of stings


          } catch (JSONException e) {
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), "Catch", Toast.LENGTH_LONG).show();
            }

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Toast.makeText(getApplicationContext(), "Error", Toast.LENGTH_SHORT).show();
            progressbar.setVisibility(View.GONE);
        }
    });

    queue.add(stringRequest);

Answer 2

public static void main(String[] args) {
//building your jsonObject(took only the 1st four ;P )
        JSONObject objJsonObject = new JSONObject();
        objJsonObject.put("THR", "تهران");
        objJsonObject.put("MHD", "مشهد");
        objJsonObject.put("KIH", "کیش");
        objJsonObject.put("IFN", "اصفهان");
        String [] strArray= new String[objJsonObject.length()];
        int i = 0;
//adding your required data into a array
        for (String key: objJsonObject.keySet()) {
            strArray[i] = objJsonObject.getString(key);
            i++;
        }
//printing your data
        for (int j = 0; j < strArray.length; j++) {
            System.out.println(strArray[j]);
        }
}

希望这有帮助