我的程序中的无限dowhile循环(java)
我的第一个Java程序有问题。我试图复制一个你用火柴玩的游戏,但是这个程序从来不会在应该的时候停止
当我输入像6,3,2,1或7,3,2,1这样的数字时,循环应该停止在那里,但它只是继续到下一个回合,就好像什么都没有发生一样,即使变量有正确的值,并且应该匹配结束条件
我很确定问题在于主循环的while部分(在最末端),但我看不到它!这可能是显而易见的,但是
以下是完整的源代码(游戏规则如下):
import java.util.Scanner;
public class JeuDeNim {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
//Starting the game
int totalMatches;
do {
System.out.println("How many matches do you want to play with? "
+ "(from 6 to 60)");
totalMatches = sc.nextInt();
}
while(totalMatches < 6 || totalMatches > 60);
int matchesPlayer1 = 0;//to keep track of
int matchesPlayer2 = 0;//the previous round
int i = 1;//to know whose turn it is
do{
//player 1
if(!(i % 2 == 0)) {//if odd number, player 1
//round 1
if(i == 1) {
do {
System.out.println("Player 1: How many matches do you "
+ "want to pick? (1, 2 or 3)");
matchesPlayer1 = sc.nextInt();
}
while(matchesPlayer1 < 1 || matchesPlayer1 > 3);
totalMatches = totalMatches - matchesPlayer1;
i++;
}
//odd round x
else {
do {
System.out.println("Player 1: How many matches do you "
+ "want to pick this turn?");
matchesPlayer1 = sc.nextInt();
if(totalMatches - matchesPlayer1 < 0) {
System.out.println("Pick a smaller number");
//totalMatches cannot be negative
} else if(matchesPlayer1 == matchesPlayer2) {
System.out.println("You cannot pick the same number "
+ "of matches as Player 2");
}
}
while(matchesPlayer1 < 1 || matchesPlayer1 > 3
|| (totalMatches - matchesPlayer1 < 0)
|| (matchesPlayer1 == matchesPlayer2));
totalMatches = totalMatches - matchesPlayer1;
if(totalMatches == 0
|| (totalMatches == 1 && matchesPlayer1 == 1)) {
System.out.println("Player 1 Wins!");
}
i++;
}
}
//player 2
else {
//round 2
if(i == 2) {
do {
System.out.println("Player 2: How many matches do you "
+ "want to pick? (1, 2 or 3)");
matchesPlayer2 = sc.nextInt();
if(matchesPlayer2 == matchesPlayer1) {
System.out.println("You cannot pick the same "
+ "number of matches as Player 2");
}
}
while(matchesPlayer2 < 1 || matchesPlayer2 > 3
|| matchesPlayer2 == matchesPlayer1);
totalMatches = totalMatches - matchesPlayer2;
i++;
}
//even round x
else {
do {
System.out.println("Player 2: How many matches do you "
+ "want to pick this turn?");
matchesPlayer2 = sc.nextInt();
if (totalMatches - matchesPlayer2 < 0) {
System.out.println("Pick a smaller number");
//totalMatches cannot be negative
} else if(matchesPlayer2 == matchesPlayer1) {
System.out.println("You cannot pick the same number "
+ "of matches as Player 1");
}
}
while(matchesPlayer2 < 1 || matchesPlayer2 > 3
|| (totalMatches - matchesPlayer2 < 0)
|| (matchesPlayer2 == matchesPlayer1));
totalMatches = totalMatches - matchesPlayer2;
if(totalMatches == 0
|| (totalMatches == 1 && matchesPlayer2 == 1)) {
System.out.println("Player 2 Wins!");
}
i++;
}
}
System.out.println("totalMatches: " + totalMatches + " "
+ "matchesPlayer1: " + matchesPlayer1 + " " + "matchesPlayer2: "
+ matchesPlayer2);//to check that everything is working. It is not...
}
while(totalMatches > 0
|| !(!(i % 2 == 0) && totalMatches == 1 && matchesPlayer1 == 1)
|| !((i % 2 == 0) && totalMatches == 1 && matchesPlayer2 == 1));
}
}
以下是游戏规则:这是一个两人游戏,玩家轮流选择比赛(1、2或3),并且不能选择与其他玩家相同数量的比赛:如果玩家一选择2场比赛,玩家二必须选择1或3场比赛。无法再选择比赛的玩家将输掉比赛,这意味着有两种结局:没有更多比赛,或者有1场比赛,但另一名玩家在上一轮中选择了1场
# 1 楼答案
查看最后一个
while
循环中的条件这意味着只要还剩任何比赛,循环就会重复,或者不是轮到1号球员还剩1场比赛并选择1场比赛,或者不是轮到2号球员还剩1场比赛并选择1场比赛
这永远不会发生,因为(除其他原因外)它需要
i%2==0
和i%2 != 0
。将||
切换到&&
,应该可以解决问题。正如评论中指出的,你还需要反转玩家的回合检查,因为回合计数器已经增加了这个点您希望在这里使用
&&
而不是||
,就像在代码中的其他地方一样,是因为您检查了一个不同的概念。每隔一次,您都会检查循环应该重复的原因。这一次,检查循环应该结束的原因,并否定它们。如果有疑问,请实际插入用于比较的值,并查看其计算结果是否符合您认为应该的值# 2 楼答案
比赛结束时,没有比赛了。所以
while(totalMatches > 0);
就足够了删除不必要的行:
|| !(!(i % 2 == 0) && totalMatches == 1 && matchesPlayer1 == 1) || !((i % 2 == 0) && totalMatches == 1 && matchesPlayer2 == 1));