如何在Java中操作2D数组数据

Question

我有一个清单，列出了个人在一周内完成任务的开始和停止时间

当他们更改任务时，会生成一个新条目

此信息存储在2D数组中。-我想循环这个数组，并将数据存储在另一个数组中

在新的2D数组中，我希望一行显示特定日期的人

因此，如果第一个数组存储：（Person、Day、In、Out、Total）

{{"John","Mon","08:00","12:00","4.00"},
 {"John","Mon","12:00","17:00","5.00"},
 {"John","Tue","08:00","17:00","9.00"},
 {"Mike","Tue","08:00","11:00","3.00"}
 {"Mike","Tue","11:00","17:00","6.00"}};

我希望第二个数组存储：

    {{"John","Mon","08:00","17:00","9.00"},
     {"John","Tue","08:00","17:00","9.00"},
     {"Mike","Tue","08:00","17:00","9.00"}};

以下是我目前的代码：

 public class CompArrayTest {

public static void main(String args[]){

    String[][] End = new String [5][5];
    String[][] Start = {{"John","Mon","08:00","12:00","4.00"},
                        {"John","Mon","12:00","17:00","5.00"},
                        {"John","Tue","08:00","17:00","9.00"},
                        {"Mike","Tue","08:00","11:00","3.00"},
                        {"Mike","Tue","11:00","17:00","6.00"}};



    //print start 
    for(int i = 0; i<Start.length; i++){ 
      for(int j = 0; j<Start.length; j++){
          System.out.print(Start[i][j]+" ");

      }//j end
     System.out.print("\n");
    }//i end

    //change end 
    for(int i = 0; i<Start.length; i++){ 
        String name = Start[i][0];
        String day = Start[i][1];
        String In = Start[i][2];
        String Out = Start[i][3];
        String Total = Start[i][4];

       //look through End
      for(int j = 0; j<5; j++){

      String eN= End[j][0];
      String eD= End[j][1];

      if(eN==name && eD==day){
      //change end time
      End[j][3]=Start[i][3];

      //parse and add times
      double TS = Double.parseDouble(Start[i][4]);
      double TE = Double.parseDouble(End[i][4]);

      double ans = TS + TE;
      String ANS = ans+"";

      End[j][4]= ANS;


      } else {



      End[j][0] = name;
      End[j][1] = day;
      End[j][2] = In;
      End[j][3] = Out;
      End[j][4] = Total;


      }//else end


      }//j end
     System.out.print("\n");
    }//i end

 //print end 
    for(int i = 0; i<Start.length; i++){ 
      for(int j = 0; j<Start.length; j++){
          System.out.print(End[i][j]+" ");

      }//j end 
     System.out.print("\n");
    }//i end

}//main end

Answer 1

感谢您的帮助，但我设法找到了一个解决方案，解决了在开始数组中循环时出现的问题

 for (int i = 0; i < Start.length; i++) {
        String name = Start[i][0];
        String day = Start[i][1];
        String In = Start[i][2];
        String Out = Start[i][3];
        String Total = Start[i][4];

        int emptyLine = 0;
        int lastLine = 0;

        //gets first emptyline, lastfilled line
        for (int j = 0; j < 5; j++) {

            if (End[j][0] == null) {
                emptyLine = j;
                if (j > 0) {
                    lastLine = j - 1;

                }
                break;
            }
        }//get Empty

        String eN = End[lastLine][0];
        String eD = End[lastLine][1];

        if (eN == name && eD == day) {
            //change end time
            End[lastLine][3] = Start[i][3];

            //parse and add times
            double TS = Double.parseDouble(Start[i][4]);
            double TE = Double.parseDouble(End[lastLine][4]);

            double ans = TS + TE;
            String ANS = ans + "";

            End[lastLine][4] = ANS;

           // System.out.println("Test If " + name + " " + day + " " + In + " " + Out + " " + Total);

        } else {

            End[emptyLine][0] = name;
            End[emptyLine][1] = day;
            End[emptyLine][2] = In;
            End[emptyLine][3] = Out;
            End[emptyLine][4] = Total;

           // System.out.println("Test Else " + name + " " + day + " " + In + " " + Out + " " + Total);

        }//else end


    }//i end

这给了我想要的输出。不过，谢谢你关于制作员工对象的建议，我以后会用它

启动阵列

约翰周一08:00 12:00 4.0
约翰周一12:00 17:00 5.0
约翰星期二08:00 17:00 9.0
迈克星期二08:00 11:00 3.0
迈克周二11:00 17:00 6.0

端阵列

约翰周一08:00 17:00 9.0
约翰星期二08:00 17:00 9.0
迈克星期二08:00 17:00 9.0
空值
空空空空空空

Answer 2

我建议你使用一个object Employee来完成一个会话集合。 对象会话：

public class Session {
    private String day;
    private String in;
    private String out;
    private String total;

    Session(String day, String in, String out, String total){
        this.setDay(day);
        this.setIn(in);
        this.setOut(out);
        this.setTotal(total);
}
    public String getDay() {
        return day;
    }
    public void setDay(String day) {
        this.day = day;
    }
    public String getIn() {
        return in;
    }
    public void setIn(String in) {
        this.in = in;
    }
    public String getOut() {
        return out;
    }
    public void setOut(String out) {
        this.out = out;
    }
    public String getTotal() {
        return total;
    }
    public void setTotal(String total) {
        this.total = total;
    }   
}

以及目标员工：

public class Employee {
    private String name;
    private List<Session> sessions;

    Employee(String name){
        this.name = name;
        this.sessions = new ArrayList<Session>();
    }

    public boolean addSession(String day, String in, String out, String total){
        return sessions.add(new Session(day, in, out, total));
    }
}

但实施员工行为仍有一个问题。在我下面的例子中，如果Mike出现中断，会发生什么情况：

{{"John","Mon","08:00","12:00","4.00"},
 {"John","Mon","12:00","17:00","5.00"},
 {"John","Tue","08:00","17:00","9.00"},
 {"Mike","Tue","08:00","11:00","3.00"}
 {"Mike","Tue","12:00","17:00","6.00"}
};

Answer 3

1）你可以为Employee创建一个类，但我的答案将涉及你选择2D数组的风格

2）不应该为完成的数组分配5乘5的数组。当然，列的数量可能是5，但是如果您的示例中有重复的列呢

为了解决第二个问题，我将使用for循环和一个计数器变量来迭代每个人的标识变量。在这种情况下，我假设每个“名字”都不同，所以你可以检查名字和日期是否相同，如果是，不要增加计数器。最后，你有一个完美大小的2D阵列

下一步，创建一个算法来计算给定进出时间的工作小时数

最后，使用另一个for循环，检查名称和日期是否相同。如果是这样，把这些小时加起来，用这些数据创建一个新行