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java如何为Postman的二进制类型的请求体构建RestTemplate?

我正在尝试使用RestTemplate调用第三方服务。但是,当我试图通过Java代码调用服务时,它抛出了BadRequest错误。 由于我不知道如何为API构建Resttemplate,因此我请求在这里获得关于如何为此类请求构建请求体的建议,同时请查看我现有的代码,并帮助我找出代码中的错误

邮递员请求的外观: Postman view of request

以下是Postman中形成的代码片段:

 OkHttpClient client = new OkHttpClient();
Request request = new Request.Builder()
  .url("")
  .post(null)
  .addHeader("Authorization", "************")
  .addHeader("User-Agent", "PostmanRuntime/7.13.0")
  .addHeader("Accept", "*/*")
  .addHeader("Cache-Control", "no-cache")
  .addHeader("Postman-Token", "**********")
  .addHeader("Host", "**************")
  .addHeader("accept-encoding", "gzip, deflate")
  .addHeader("content-length", "160200")
  .addHeader("Connection", "keep-alive")
  .addHeader("cache-control", "no-cache")
  .build();

Response response = client.newCall(request).execute();

//其中file的类型为file

LinkedMultiValueMap<String, Object> map = new LinkedMultiValueMap<>();
map.add("file", new ClassPathResource(file));

HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.TEXT_PLAIN);

HttpEntity<LinkedMultiValueMap<String, Object>> requestEntity = new    
HttpEntity<LinkedMultiValueMap<String, Object>>(
                map, headers);
ResponseEntity<String> result = template.get().exchange(
                contextPath.get() + path, HttpMethod.POST, requestEntity,
                String.class);

我想成功呼叫第三方实体并获得响应


共 (1) 个答案

  1. # 1 楼答案

    ResponseEntitybyte[]类型一起使用,而不使用内容类型:

    InputStream inputStream = new ClassPathResource("myFile.jpg").getInputStream();
    byte[] data = IOUtils.toByteArray(inputStream);
    HttpEntity<byte[]> requestEntity = new HttpEntity<>(data);
    
    restTemplate.exchange("url", HttpMethod.POST, requestEntity , String.class);