java非单词字符分隔符“\W”将“逗号+空格”计算为一个字符
给定一个与正则表达式[A-Za-z !,?._'@]+
匹配的字符串,我想将该字符串拆分为标记。标记是一个或多个连续的英文字母。然后,我想打印令牌的数量。这是我的代码:
public class mySolution {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.nextLine();
String [] parts = new String[1159];
parts = s.split("\\W");
System.out.println(parts.length);
for(int i = 0; i< parts.length; i++) {
System.out.println(parts[i]);
}
scan.close();
}
}
这是我尝试的输入:
He is a very very good boy, isn't he?
这是我收到的输出:
11
He
is
a
very
very
good
boy
isn
t
he
正如你所看到的,一切都很好,但是代币的数量是11,而它应该是10!我相信非单词字符分隔符"\W"
将“逗号+空格”作为一个字符计数!我说得对吗
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