数组如何在java中分割最后一个值为空时的csv行

Question

我有逗号分隔的值，如下所示

String s1 = "a, b, c, d, e";
String s2 = "a, , , d, ";
String s3 = "a, b, c, d, ";

我需要用“，”分开这个字符串。但是值的数量应该是5。我的意思是最后一个空值应该出现在输出数组中。 有什么解决办法吗

Answer 1

您可以使用拆分方法：

String[] S2 = s2.split(",");

为了证明它有效->

System.out.println(S2.length);
for (String str : S2) {
     if (str.equals(" ")) {
         System.out.println("Space");
     } else {
         System.out.println(str);
}

Answer 2

我用绳子。split（String regex）方法，并查看数组有5个元素。我希望这能回答你的问题

package net.javapedia.StringSplitExample;

public class Main {

    public static void main (String[] s) {

        String s1 = "a, b, c, d, e";
        String s2 = "a, , , d, ";
        String s3 = "a, b, c, d, ";
        // This is the String that issue is reported
        String s4 = "a,b,c,d,";
        String s5 = "a,b,c,d,";

        String[] s1Array= s1.split(",");
        String[] s2Array= s2.split(",");
        String[] s3Array= s3.split(",");
        //Below split ignore empty string
        String[] s4Array= s4.split(",");
        //Below split doesn't
        String[] s5Array= s5.split(",",-1);

        System.out.println(s1Array.length);
        System.out.println(s2Array.length);
        System.out.println(s3Array.length);
        //Prints 4
        System.out.println(s4Array.length);
        //Prints 5 :)
        System.out.println(s5Array.length);
    }

}

输出：

Reference