java如何最小化输入异常
我有以下代码,可以很好地完成工作,但正如您所看到的,它非常冗长,可能会令人困惑:
private void addRecord() {
String firstName = JOptionPane.showInputDialog("First Name: ");
if (firstName.length() <= 0){
JOptionPane.showMessageDialog(null, "That is not a valid input.","Input error",JOptionPane.ERROR_MESSAGE);
addRecord();
}//end if
String lastName = JOptionPane.showInputDialog("Last Name: ");
if (lastName.length() <= 0){
JOptionPane.showMessageDialog(null, "That is not a valid input.","Input error",JOptionPane.ERROR_MESSAGE);
addRecord();
}//end if
String a = JOptionPane.showInputDialog("Student Number: ");
int studentNumber = Integer.parseInt(a);
if (a.length() <= 0 || studentNumber == 0){
JOptionPane.showMessageDialog(null, "That is not a valid input.","Input error",JOptionPane.ERROR_MESSAGE);
sortMenu();
}//end if
String major = JOptionPane.showInputDialog("Major: ");
if (major.length() <= 0){
JOptionPane.showMessageDialog(null, "That is not a valid input.","Input error",JOptionPane.ERROR_MESSAGE);
addRecord();
}//end if
String b = JOptionPane.showInputDialog("GPA: ");
double gpa = Double.parseDouble(b);
if (b.length() <= 0 || gpa > 4.0){
JOptionPane.showMessageDialog(null, "That is not a valid input.","Input error",JOptionPane.ERROR_MESSAGE);
sortMenu();
}//end if
tree.addNode(studentNumber, firstName, lastName, major, gpa);
}//end addRecord
有没有更好的方法,我可以写这个来检查每个输入,而不必每个输入都有if语句?我想尽量减少这种情况
# 1 楼答案
试试这个:
额外条件包括
or
参数