将嵌套列表改为词典列表的理解

Question

我已经把数据输入到列表结构中

[['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '], 
['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n   long string that needs to be split up '], 
['keychain: "keychainname.keychain-db"', 
'version: 512', 
'class: 0x0000000F ', 
'attributes:\n    long string that needs to be split up']]

我试着用理解力把列表中的每一项都分成一个字典，格式是

['{'keychain': 'keychainname.db', 
'version': '512', 
'class': '0x0000000F', 
'attribute':\n   long string containing : and \n that needs to be split up into a dictionary (by newline) of dictionaries (by regex and/or split() function) '}']

下面的for循环似乎有效

newdata = []
for item in data:
    eachdict = {}
    for each in item:
        new = each.split(':', 1)
        eachdict[new[0]] = new[1]
        newdata.append(eachdict)

但我的理解力并没有

newdata = [[{key:value for item in data} for line in item] for key, value in (line.split(':', 1))]

这个理解是正确的，但是它没有正确的嵌套

newdata = [{key:value for item in data} for key, value in (item.split(':', 1),)]

我刚刚开始学习理解，我已经能够成功地使用它们将数据转换成嵌套列表的上述格式，但是当我下三级并从列表切换到字典时，我很难理解嵌套。你知道吗

我很想得到一些关于如何解决这个问题的建议。你知道吗

为了获得额外的积分，我还需要将attributes键中的长字符串拆分为一个字典字典。我想能够参考'Alis'键，标签'键等。如果我先学习如何使用上面例子中的嵌套理解，我可能自己就能弄清楚。你知道吗

attributes:\n
    "alis"<blob>="com.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"\n
    "cenc"<uint32>=0x00000003 \n
    "ctyp"<uint32>=0x00000001 \n
    "hpky"<blob>=0xB7262C7D5BCC976744F8CA6DE5A80B755622D434  "\\267&,}[\\314\\227gD\\370\\312m\\345\\250\\013uV"\\3244"\n
    "issu"<blob>=0x306E3128302606035504030C1F4170706C6520436F72706F726174652056504E20436C69656E7420434120313120301E060355040B0C1743657274696669636174696F6E20417574686F7269747931133011060355040A0C0A4170706C6520496E632E310B3009060355040613025553  "0n1(0&\\006\\003U\\004\\003\\014\\037Company Corporate VPN Client CA 11 0\\036\\006\\003U\\004\\013\\014\\027Certification Authority1\\0230\\021\\006\\003U\\004\\012\\014\\012Company Inc.1\\0130\\011\\006\\003U\\004\\006\\023\\002US"\n
    "labl"<blob>="com.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"\n
    "skid"<blob>=0xB7262C7D5BCC976744F8CA6DE5A80B755622D434  "\\267&,}[\\314\\227gD\\370\\312m\\345\\250\\013uV"\\3244"\n    "snbr"<blob>=0x060A02F6F9880D69  "\\006\\012\\002\\366\\371\\210\\015i"\n
    "subj"<blob>=0x3061315F305D06035504030C56636F6D2E6170706C652E6973742E64732E6170706C65636F6E6E656374322E70726F64756374696F6E2E76706E2E35443541463943353235433235333530453943443543454245443832344246443630453432313130  "0a1_0]\\006\\003U\\004\\003\\014Vcom.company.companyvpn.production.vpn.5D5AF9C525C25350E9CD5CEBED824BFD60E42110"' 

对于上下文

我在Mac上使用“security dump keychain”的输出来创建一个很好的Python数据结构来查找密钥。这个命令的check\u输出是一个长字符串，其中包含一些不一致的格式和嵌入的新行，我需要清除这些内容，以便将数据放入字典列表中。你知道吗

对于那些对Mac管理主题感兴趣的人来说，这样我们就可以在重置AD密码时删除保存activedirectory密码的项目，这样帐户就不会被Outlook反复显示旧密码来交换而锁定。你知道吗

Answer 1

这里可能有一种方法：

data = [['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '],  ['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n   long string that needs to be split up '],  ['keychain: "keychainname.keychain-db"',  'version: 512',  'class: 0x0000000F ',  'attributes:\n    long string that needs to be split up']]

result = [dict([item.split(':', 1) for item in items]) for items in data]

>>> [{'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n   long string containing : and \n that needs to be split up into a list (by newline) of dictionaries (by regex and/or split() function) '}, {'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n   long string that needs to be split up '}, {'keychain': ' "keychainname.keychain-db"', 'version': ' 512', 'class': ' 0x0000000F ', 'attributes': '\n    long string that needs to be split up'}]

split将每个字符串分解为键、值对。 内部列表将遍历单个项中的每个键、值对。外部列表通过主列表中的每个项目循环。你知道吗