如何在pygame中绘制类对象列表?

2024-06-25 23:36:16 发布

您现在位置:Python中文网/ 问答频道 /正文

我试图在pygame中创建空间入侵者(我是初学者,这只是我的第二个游戏),我创建了一个外星物体列表:

numOfAliens = 24
aliens = []

# An alien class containing an x, y, width, and height value
class alien:
    x, y = 0, 0
    width, height = 20, 20

# Loops 24 times and adds alien to the class
for i in range(numOfAliens):
    aliens.append(alien)

我还有一段代码,加上5和每个x值的宽度来分隔外星人:

for i in aliens:
    i.x += 5 + i.width
    print(i.x, i.y, i.width, i.height)

打印告诉我,前两块代码运行良好,没有任何问题,当我尝试将其绘制到pygame窗口时,问题出现了:

# Loops 24 times, drawing each alien to the window
for i in range(numOfAliens):
        pygame.draw.rect(win, GREEN, (aliens[i].x, aliens[i].y, aliens[i].width, aliens[i].height))

当然外星人[i].x会得到列表中每个对象的x值,但它不会。 如果我在这个for循环中添加一个print(“hi”),它会无限地打印出“hi”,而它应该只循环24次,而且窗口上什么也没有画出来,有没有办法解决这个问题?你知道吗

以下是所有需要的代码:

import pygame
pygame.init()

clock = pygame.time.Clock()

# Window
win_width, win_height = 500, 500

win = pygame.display.set_mode((win_width, win_height))
pygame.display.set_caption("Space Invaders")


# Colours
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GREEN = (30, 224, 27)


# Player
player_width, player_height = 20, 20
player_x, player_y = int((win_width / 2) - (player_width / 2)), (win_height - 50)
player_vel = 10
isShooting = False
isAlive = True


# Bullet
bullet_width, bullet_height = 4, 16
bullet_x, bullet_y = player_x, player_y
bullet_vel = 5


# Aliens
numOfAliens = 24
aliens = []

class alien:
    x, y = 0, 0
    width, height = player_width, player_height

for i in range(numOfAliens):
    aliens.append(alien)

for i in aliens:
    i.x += 5 + i.width
    print(i.x, i.y, i.width, i.height)

# Draw Function
def draw():
    win.fill(BLACK)
    pygame.draw.rect(win, GREEN, (player_x, player_y, player_width, player_height))

    for i in aliens:
        pygame.draw.rect(win, GREEN, (i.x, i.y, i.width, i.height))

    if isShooting:
        pygame.draw.rect(win, WHITE, (bullet_x, bullet_y, bullet_width, bullet_height))

    pygame.display.update()

# Game Loop
run = True
while run:
    clock.tick(20)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()

    if keys[pygame.K_LEFT] and player_x > 0:
        player_x -= player_vel

    if keys[pygame.K_RIGHT] and player_x < win_width - player_width:
        player_x += player_vel

    if keys[pygame.K_SPACE] and not(isShooting):
        bullet_y = player_y
        bullet_x = int(player_x + (player_width / 2))
        isShooting = True

    if bullet_y + bullet_height <= 0:
        isShooting = False

    if isShooting:
        bullet_y -= bullet_vel

    draw()

pygame.quit()

Tags: andinforifwidthpygamewinplayer
1条回答
网友
1楼 · 发布于 2024-06-25 23:36:16

实际上你没有创建任何外星人的实例。alien只是类本身。你知道吗

aliens.append(alien)

要创建类alien的实例,必须添加括号:
Class Objects

aliens.append(alien())

请注意,python中的类名应以大写字母开头。
Style Guide for Python Code - Class Names

为类Alien添加一个带有x和y坐标参数的构造函数,并为位置和大小创建instance attributes。 根据控制变量i计算外星生物的位置:

numOfAliens = 24
aliens = []

class Alien:
    def __init__(self, x, y):
        self.x, self.y = x, y
        self.width, self.height = player_width, player_height

for i in range(numOfAliens):
    aliens.append(Alien(i * (5+player_width), 0))

相关问题 更多 >