python2.7中for循环中使用的定义函数

Question

我的python脚本是否有问题？你知道吗

from BeautifulSoup import BeautifulSoup
import requests
import re
from collections import defaultdict
import itertools
import pandas as pd

def wego(weburl,annot):
    print 'Go Term: ', weburl.split('=')[-1]
    html=requests.get(weburl).text
    soup=BeautifulSoup(html)
    desc=r"desc=\".*\""
    print "GO leave 2 term:",(re.findall(desc,str(soup))[0].split('"')[1])
    pattern=r"Unigene.*A"
    idDF = pd.DataFrame(columns=['GeneID']) #creates a new datafram
    idDF['GeneID'] = pd.Series(re.findall(pattern,str(soup))).unique()
    print "Total Go term is :",idDF.shape[0]
    old=pd.read_csv(annot,usecols=[0,7,8])
    getset=pd.merge(left=idDF,right=old,left_on=idDF.columns[0],\
    right_on=old.columns[0])
    updown=getset.groupby(getset.columns[1]).count()
    print updown
    print "Max P-value: ","{:.3e}".format(getset['P-value'].max())

with open("gourl.txt") as ur:
    d=[]
    for url in ur:
    we=wego(url,annot="file.csv")
    d.append(we)

我的古尔.txt文件是一行一行的url

http://stackoverflow.com/questions=1
http://stackoverflow.com/questions=2

我的问题是，脚本中只有一个url时，为什么脚本可以成功古尔.txt文件和失败时有多个？

错误如下：

IndexError: list index out of range
IndexErrorTraceback (most recent call last)
<ipython-input-79-a852fe95d69c> in <module>()
  2     d=[]
  3     for url in ur:
----> 4         we=wego(url,annot="file.csv")
  5         d.append(we)
<ipython-input-4-9fdf25e75434> in wego(weburl, annot)
  5     soup=BeautifulSoup(html)
  6     desc=r"desc=\".*\""
----> 7     print "GO leave 2 term:",(re.findall(desc,str(soup))
 [0].split('"')[1])
  8     pattern=r"Unigene.*A"
  9     idDF = pd.DataFrame(columns=['GeneID']) #creates a new dataframe 
 IndexError: list index out of range

Answer 1

很高兴问题有了答案。 问题在我的古尔.txt文件读取时。我将展示以下内容：

>>> with open("wegourl.txt") as ur:
...     d=[]
...     for url in ur:
...         print url
...         

http://stackoverflow.com/questions=1

http://stackoverflow.com/questions=2

毫无疑问，换行引起的空行不是合法的URL，中断了这个脚本。 我可以在读取文件时修改\n just rid of：url=url.strip('\n')