擅长:python、mysql、java
<p>为什么不尝试在python中使用散列集来做一些更简单的事情呢。你知道吗</p>
<pre><code>def solution(participant, completion):
answer = []
completion_set = set(completion)
for p in participant:
if p not in completion_set:
answer.append(p)
return answer
print(solution(["leo", "kiki", "eden"],["eden", "kiki"]))
</code></pre>
<p>也可以通过普通列表来实现。你知道吗</p>