如何从函数的返回值中获取变量？

Question

我想把发送消息!player1或!player2的返回的播放器放到一个简短的列表中，以便我以后可以使用它们，但是我似乎找不到如何从函数内部的函数中获取返回的变量。我看到了一些关于闭包的东西，我认为这是，但即使按照这个例子，我似乎无法得到返回值，所以我可以分配它们。你知道吗

    def players(sender, event):

    def getplayer():

        msg = event.parsed[0]['msg']

        if msg == '!player1':
            BotBasicFunction.sendmsg(msgg='{} has joined the game!'.format(hasplayer()))
            hasplayer()

        if msg == '!player2':
            BotBasicFunction.sendmsg(msgg='{} has joined the game!'.format(hasplayer()))
            hasplayer()

    def hasplayer():
        invoker = event.parsed[0]['invokername']
        return invoker

    parsedmsg = event.parsed[0]['msg']

    players = [getplayer(), getplayer(), getplayer(), getplayer()]

    if parsedmsg == '!players':
        BotBasicFunction.sendmsg(msgg='{}'.format(players))