擅长:python、mysql、java
<p><code>time.sleep()</code>是一个很好的解决方案,但是当您想继续时,也可以让Python请求输入。我知道这很原始。你知道吗</p>
<pre class="lang-py prettyprint-override"><code>if counter % 500 == 0: # make the counter start at 1
val = input("\nContinue? [y/n]: ")
if val == 'y':
pass # manually unpause the looping, whenever you want
elif val == 'n':
break # interrupt for loop
</code></pre>