擅长:python、mysql、java
<p>下面是修复错误的片段:</p>
<pre><code>lst = ['iamcool', 'Noyouarenot']
stopwords = ['iamcool']
resultwords = [word for word in lst if word not in stopwords]
result = ' '.join(resultwords)
print result
</code></pre>
<p>另一种可能的解决方案是假设您的输入列表和非索引词列表不关心顺序和重复项:</p>
<pre><code>print " ".join(list(set(lst)-set(stopwords)))
</code></pre>