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<p>我有一个带有文件名的列表和一个带有过滤词的嵌套列表。筛选器列表有3个列表,每个列表的子列表长度不同。你知道吗</p>
<p>如何遍历列表并使用<code>and</code>函数?由于<code>['employer', 'finance']</code>和<code>['employer', 'adress']</code>的差异,它需要检查列表中的所有值。你知道吗</p>
<pre><code>filter = [
['employer','finance'],
['manifest'],
['epmloyer','adress','home']
]
file_list = [
'01012017_employer_finance.txt',
'25102017_cargo_manifest.txt',
'12022014_employer_finance.txt',
'12022018_epmloyer_home_adress.txt',
'12032016_employer_home_adress.rtx'
]
"""search for financial file"""
if filter[0][0] in file_list[0] and filter[0][1] in file_list[0]:
print('Financial file found')
"""search for cargo manifest"""
if filter[1][0] in file_list[1]:
print('Cargo manifest found')
"""search for adress file"""
if filter[2][0] in file_list[2] and filter[2][1] in file_list[2] and filter[2][2] in file_list[2]:
print('Financial file found')
</code></pre>
<p>到目前为止,我设法得到下面的代码。但是我如何处理不同长度的列表呢?变量的使用,例如:<code>filter[x][z]</code>代替<code>filter[1][0]</code></p>
<pre><code>"""loop through the file_list"""
for file in file_list:
print("Identify file:", file)
#identify file in list with lists in it
if filter[0][0] in file and filter[0][1] in file:
print('***Financial file found')
</code></pre>
<p>好的,我使用了给定的代码。你知道吗</p>
<pre><code>file_list = [
'01012007-1_employer_finance.txt',
'25102013-2_cargo_manifest.txt',
'12022018-3_epmloyer_home_adress.txt',
'12022028-4_epmloyer_work_adress.txt',
'01012011-5_employer_finance.txt'
'01012007-12_employer_finance.txt',
'25102013-23_cargo_manifest.txt',
'12022018-34_epmloyer_home_adress.txt',
'12022028-45_epmloyer_work_adress.txt',
'01012011-56_employer_finance.txt'
]
"""Dictionary files"""
filters = {
'finance': ['employer','finance'],
'manifest': ['manifest'],
'address': ['epmloyer', 'adress', 'home'],
'addres': ['epmloyer', 'adress', 'work']
}
"""Tweede oplossing op stackoverflow"""
"""Loop through the nested list"""
def matches(filter, filename):
return all(x in filename for x in filter)
def get_filename(filter, files):
for f in files:
if matches(filter, f):
return f
for label, filter in filters.items():
file = get_filename(filter, file_list)
if file:
#print(f'Found {label} file: {file}')
pass
found_files = {label: get_filename(filters, file_list) for label, filters in filters.items()}
print(found_files)
</code></pre>
<p>结果是:</p>
<pre><code>{'finance': '01012007-1_employer_finance.txt', 'manifest': '25102013-2_cargo_manifest.txt', 'address': '12022018-3_epmloyer_home_adress.txt', 'addres': '12022028-4_epmloyer_work_adress.txt'}
</code></pre>
<p>然而,名单应该更大。你知道吗</p>