不会添加计数大师思想游戏Python

Question

import random
thenum = random.randint(1000, 9999)
print (thenum)
tally = 1
guessone = int(input("What is your first guess?: "))
strguessone = str(guessone)
strthenum = str(thenum)
if strguessone [0] == strthenum [0]:
    tally + 1
if  strguessone [1] ==  strthenum [1]:
    tally + 1
if strguessone [2] == strthenum [2]:
    tally + 1
if  strguessone [3] ==  strthenum [3]:
    tally + 1

print (tally)
if tally == 5:
    print ("You Win")

当我运行这个代码时，我只从print taly得到一个响应，为什么我在if语句中添加了taly，我知道我应该使用循环，但我想这就是我想要做的

Answer 1

应该使用+=运算符而不是+运算符。你知道吗

import random
thenum = random.randint(1000, 9999)
print (thenum)
tally = 1
guessone = int(input("What is your first guess?: "))
strguessone = str(guessone)
strthenum = str(thenum)
if strguessone [0] == strthenum [0]:
    tally += 1
if  strguessone [1] ==  strthenum [1]:
    tally += 1
if strguessone [2] == strthenum [2]:
    tally += 1
if  strguessone [3] ==  strthenum [3]:
    tally += 1

print (tally)
if tally == 5:
    print ("You Win")

Answer 2

当你这样做的时候-

tally + 1

它会计算该表达式的结果，但会丢弃结果，因为您没有指示Python解释器对结果执行任何操作。如果希望tally增加1，则必须将结果赋回tally。示例-

tally += 1

Answer 3

tally + 1语句所做的就是计算tally加1的值。它不会保存新值。您需要改为执行tally = tally + 1。但是，在这种情况下，您可以直接比较数字，而不是将两个值都转换为字符串并比较这些字符串（您可以这样做，而不必逐个手动比较每个字符）：

import random
thenum = random.randint(1000, 9999)
print (thenum)
guessone = int(input("What is your first guess?: "))
if thenum == guessone:
    print ("You Win")