如何在for循环中重新分配cuda gpu设备阵列而不耗尽内存?

2024-10-03 04:40:11 发布

您现在位置:Python中文网/ 问答频道 /正文

看看这个代码:

 (cudavenv) C:\main\FemtoTest\Library\Python\libImageProcess\trunk\src\libImageProcess>python
Python 3.7.4 (default, Aug  9 2019, 18:34:13) [MSC v.1915 64 bit (AMD64)] :: Anaconda, Inc. on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import numpy as np
>>> from numba import cuda
>>> for i in range(26):
...     arr = np.zeros((17, 8025472),dtype=np.uint32)
...     d_arr = cuda.to_device(arr)
...

成功运行与

(cudavenv) C:\main\FemtoTest\Library\Python\libImageProcess\trunk\src\libImageProcess>python
Python 3.7.4 (default, Aug  9 2019, 18:34:13) [MSC v.1915 64 bit (AMD64)] :: Anaconda, Inc. on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import numpy as np
>>> from numba import cuda
>>> class M:
...     def __init__(self):
...             self.arr = np.zeros((17, 8025472),dtype=np.uint32)
...             self.d_arr = None
...
>>> ms = [M() for _ in range(26)]
>>> for m in ms:
...     m.d_arr = cuda.to_device(m.arr)
...
Traceback (most recent call last):
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 741, in _attempt_allocation
    allocator()
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 756, in allocator
    driver.cuMemAlloc(byref(ptr), bytesize)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 294, in safe_cuda_api_call
    self._check_error(fname, retcode)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 329, in _check_error
    raise CudaAPIError(retcode, msg)
numba.cuda.cudadrv.driver.CudaAPIError: [2] Call to cuMemAlloc results in CUDA_ERROR_OUT_OF_MEMORY

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\devices.py", line 225, in _require_cuda_context
    return fn(*args, **kws)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\api.py", line 110, in to_device
    to, new = devicearray.auto_device(obj, stream=stream, copy=copy)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\devicearray.py", line 693, in auto_device
    devobj = from_array_like(obj, stream=stream)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\devicearray.py", line 631, in from_array_like
    writeback=ary, stream=stream, gpu_data=gpu_data)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\devicearray.py", line 102, in __init__
    gpu_data = devices.get_context().memalloc(self.alloc_size)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 758, in memalloc
    self._attempt_allocation(allocator)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 748, in _attempt_allocation
    allocator()
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 756, in allocator
    driver.cuMemAlloc(byref(ptr), bytesize)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 294, in safe_cuda_api_call
    self._check_error(fname, retcode)
  File "C:\Users\alex\AppData\Local\Continuum\anaconda3\envs\cudavenv\lib\site-packages\numba\cuda\cudadrv\driver.py", line 329, in _check_error
    raise CudaAPIError(retcode, msg)
numba.cuda.cudadrv.driver.CudaAPIError: [2] Call to cuMemAlloc results in CUDA_ERROR_OUT_OF_MEMORY

我认为在第一个实例中,我每次都会将dèarr重新分配给设备阵列,因此它只占用那么多内存。在第二种情况下,因为有26个实例,它每次都会在设备上创建一个新数组,最终耗尽内存。在for循环中使用完内存引用后,我需要调用什么方法来删除它?这样就可以毫无问题地运行了?你知道吗


Tags: inliblocallineusersappdatacudafile
1条回答
网友
1楼 · 发布于 2024-10-03 04:40:11

您可能希望阅读第3.3.8节here。你知道吗

当对不再需要的CUDA内存的最后一个引用被删除时,可以释放它。在第一种情况下,当d_arr被重新分配时,这种情况会发生在循环的每次传递上。在第二种情况下,它没有,因为引用保存在ms。你知道吗

我认为一个恰当的解决办法是使引用被删除。The pythonic way to do this是删除引用:

import numpy as np
from numba import cuda
class M:
    def __init__(self):
            self.arr = np.zeros((17, 8025472),dtype=np.uint32)
            self.d_arr = None

ms = [M() for _ in range(26)]
for m in ms:
    m.d_arr = cuda.to_device(m.arr)
    # do whatever it is you want to do with m.d_arr here
    m.d_arr = None

相关问题 更多 >