<p>将文件解析为单独字典的示例代码。这是通过查找组分隔符(空行)来实现的。setNames[i]是字典中setData[i]处的一组参数的名称。或者,您可以创建一个对象,该对象具有字符串<code>name</code>成员和字典<code>data</code>成员,并保留这些成员的列表。进行比较并按自己的意愿输出,这只是将输入文件以稍微不同的格式返回到命令行。你知道吗</p>
<pre><code> # The function you wrote
def make_dict(data):
return dict((line.split(None, 1)[0], line) for line in data)
# open the file and read the lines into a list of strings
with open("Config.txt" , "rb") as f:
dataConfig = f.read().splitlines()
# get rid of trailing '', as they cause problems and are unecessary
while (len(dataConfig) > 0) and (dataConfig[len(dataConfig) - 1] == ''):
dataConfig.pop()
# find the indexes of all the ''. They amount to one index past the end of each set of parameters
setEnds = []
index = 0
while '' in dataConfig[index:]:
setEnds.append(dataConfig[index:].index('') + index)
index = setEnds[len(setEnds) - 1] + 1
# separate out your input into separate dictionaries, and keep track of the name of each dictionary
setNames = []
setData = []
i = 0;
j = 0;
while j < len(setEnds):
setNames.append(dataConfig[i])
setData.append(make_dict(dataConfig[i+1:setEnds[j]]))
i = setEnds[j] + 1
j += 1
# handle the last index to the end of the list. Alternativel you could add len(dataConfig) to the end of setEnds and you wouldn't need this
if len(setEnds) > 0:
setNames.append(dataConfig[i])
setData.append(make_dict(dataConfig[i+1:]))
# regurgitate the input to prove it worked the way you wanted.
for i in range(len(setNames)):
print setNames[i]
for k in setData[i]:
print "\t" + k + ": " + setData[i][k];
print ""
</code></pre>