Django窗体，如何使用startswith验证窗体

Question

我正试图找出如何让下面的代码位工作，使一切以元组开始是有效的，例如，如果邮政编码'GU15 56L'是输入它允许邮政编码。目前只有GU15部件在工作（对于本例）。比如从哪里开始，但不确定从哪里开始。你知道吗

class PostCodeForm (forms.Form):
    pcode = forms.CharField()

    def clean_pcode(self):
        permitted = {'GU15','GF34','FG34','BT25'}
        pcode = self.cleaned_data['pcode'].lower()
        if not pcode in (permitted):
            raise forms.ValidationError("Apologies, but does not currently deliver to you postcode.")
        return pcode

提前谢谢你的帮助

Answer 1

您只需检查是否允许前4个字符：

if not pcode[:4] in permitted:
    raise forms.ValidationError("Apologies, but does not currently deliver to you postcode.")

或者

if any([pcode.startswith(code) for code in permitted]) is False:
    raise forms.ValidationError("Apologies, but does not currently deliver to you postcode.")

Answer 2

if not pcode.startswith(tuple(permitted)):
    raise ValueError()

但是您使用self.cleaned_data['pcode'].lower()，并且您的集合包含所有大写单词。试试self.cleaned_data['pcode'].upper()