如何在用户输入“y”的情况下重新启动游戏？为aftergam创建了一个用户定义的函数

Question

i=1

玩另一个游戏或退出游戏

def done():

    quitvalue=str(input("Play Again?(y/n):"))
    if quitvalue=='n' and i==0:
            SystemExit
    elif quitvalue=="y":
                i=1



#Loop to Restart Game

def rps(play1,play2):

        #Check Winner of Game
        if play1==play2:
            print("It's a tie!")
            done()

        elif play1=='r':
            if play2=='s':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()


        elif play1=='p':
            if play2=='r':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()

        elif play1=='s':
            if play2=='p':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()


#Player Input
while i==1:
    play1name=str(input("Player 1 Name?:"))
    play2name=str(input("Player 2 Name?:"))
    play1= str(input(play1name+" Choose Rock(r),Paper(p), Scissors(s):"))
    play2= str(input(play2name+" Choose Rock(r),Paper(p), Scissors(s):"))
    i=0
    rps(play1,play2)

Answer 1

这里的问题是done()函数中的i引用了deafult在函数中本地声明的变量i，而不是在程序开始时声明的全局变量i。要解决此问题，请在引用i之前在done()函数中添加global i：

def done():
    global i
    quitvalue=str(input("Play Again?(y/n):"))
    if quitvalue=='n' and i==0:
            SystemExit
    elif quitvalue=="y":
                i=1