如何在用户输入“y”的情况下重新启动游戏？为aftergam创建了一个用户定义的函数

Question

i=1

玩另一个游戏或退出游戏

def done():

    quitvalue=str(input("Play Again?(y/n):"))
    if quitvalue=='n' and i==0:
            SystemExit
    elif quitvalue=="y":
                i=1



#Loop to Restart Game

def rps(play1,play2):

        #Check Winner of Game
        if play1==play2:
            print("It's a tie!")
            done()

        elif play1=='r':
            if play2=='s':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()


        elif play1=='p':
            if play2=='r':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()

        elif play1=='s':
            if play2=='p':
                print(play1name+" Wins!")
                done()

            else:
                print(play2name+" Wins!")
                done()


#Player Input
while i==1:
    play1name=str(input("Player 1 Name?:"))
    play2name=str(input("Player 2 Name?:"))
    play1= str(input(play1name+" Choose Rock(r),Paper(p), Scissors(s):"))
    play2= str(input(play2name+" Choose Rock(r),Paper(p), Scissors(s):"))
    i=0
    rps(play1,play2)

Answer 1

你想在done()函数中raise SystemExit退出吗？你知道吗

如果是这样的话，就不需要跟踪命名含糊不清的变量i并处理范围界定问题。见here for some useful explanation。你知道吗

您还应该将玩家名称输入移出游戏循环，input()将返回一个字符串。你知道吗

我已经整理了代码并删除了一些不必要的重复部分。你知道吗

def done():
    """Prompt user to continue or exit"""
    quit_value = input("Play Again?(y/n): ").lower()
    if quit_value == 'n':
        raise SystemExit

def rps(play1, play2):
    """Play a single round of Rock, Paper, Scissors"""
    # Check Winner of Game
    if play1 == play2:
        print("It's a tie!")
    elif play1 == 'r':
        if play2 == 's':
            print(play1name + " Wins!")
        else:
            print(play2name + " Wins!")
    elif play1 == 'p':
        if play2 == 'r':
            print(play1name + " Wins!")
        else:
            print(play2name + " Wins!")
    elif play1 == 's':
        if play2 == 'p':
            print(play1name + " Wins!")
        else:
            print(play2name + " Wins!")

# get player names
play1name = input("Player 1 Name?: ")
play2name = input("Player 2 Name?: ")
# Player Input
while True:  # done() exits the program, so loop forever
    play1 = input(play1name + " Choose Rock(r),Paper(p), Scissors(s): ")
    play2 = input(play2name + " Choose Rock(r),Paper(p), Scissors(s): ")
    # resolve the plays
    rps(play1, play2)
    # check for a rematch
    done()

您可能还需要检查rps()函数中的有效移动。你知道吗

Answer 2

这里的问题是done()函数中的i引用了deafult在函数中本地声明的变量i，而不是在程序开始时声明的全局变量i。要解决此问题，请在引用i之前在done()函数中添加global i：

def done():
    global i
    quitvalue=str(input("Play Again?(y/n):"))
    if quitvalue=='n' and i==0:
            SystemExit
    elif quitvalue=="y":
                i=1