我正在研究凯撒密码的一种变体。当我输入加密的消息时,我的decrypt()
函数应该用不同的旋转值继续解密,直到出现一个公共词,例如“the”或“time”或“attack”。出于测试的目的,我使用了诸如“procedutoattackthebase”这样的消息,因此当any(word.upper() in plainText for word in subStrings)
部分运行时,它应该返回true,但是它没有返回true。我目前的代码如下:
def decrypt(encryptedMessage):
alphanumericAlphabet = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"] # List of every letter in the alphabet
message = (str(encryptedMessage).strip("\n")).upper()
subStrings = ["The", "Base", "Proceed", "North", "West", "South", "East", "Hours", "Dawn", "Attack", "Defend", "Shoot", "Bearing", "Enemy", "Position", "Move", "That", "Fast", "Time", "Rise", "Loss", "Win", "Victory"]
plainText = ""
messageFound = False
rotationValue = 0
while messageFound != True:
if any(word.upper() in plainText for word in subStrings):
messageFound = True
else:
plainText = ""
for character in message:
cipherIndex = alphanumericAlphabet.index(character.upper())
plainIndex = cipherIndex - rotationValue
if plainIndex < 0:
plainIndex += 36
plainText += alphanumericAlphabet[plainIndex]
rotationValue += 1
print "Decrypted Message:", plainText, "\n", "Rotation:", rotationValue
return plainText, rotationValue
在字母数字数字列表中为要处理的字符添加空格或去掉空格:
我想问题出在这方面
您必须检查
character.upper()
的索引,因为您的alphanumericAlphabet只包含大写字符。你知道吗相关问题 更多 >
编程相关推荐