按线型分组

Question

我有一个文件，里面有这样的行：

saldkfjaslk
    asdlkfja
    alsdkfjlk
aslkda;kdfsdlkfaj
sladkfjalskdfjlaskd
    sldkfaj
    lsadkfj
qwewrewst
se0polkjlkj
lpoerlwoej
    alskdjf
    asldkfjljlkjlk
sadlkfa

我想把以字符（不是空格）开头的行和以空格开头的消耗行组合在一起。我还想省略下一行不以空格开头的行。使用上述示例所需的输出如下所示：

[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'),
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'),
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')]

如何用Python解析这个文件？你知道吗

Answer 1

>>> regex = re.compile(r"^\S.*(?:\n\s.*)+", re.MULTILINE)
>>> [tuple(match.split()) for match in regex.findall(s)]
[('saldkfjaslk', 'asdlkfja', 'alsdkfjlk'), 
 ('sladkfjalskdfjlaskd', 'sldkfaj', 'lsadkfj'), 
 ('lpoerlwoej', 'alskdjf', 'asldkfjljlkjlk')]

说明：

^    # Start of line
\S   # Match a non-whitespace character
.*   # Match the rest of the line
(?:  # Match...
 \n  #  a newline character
 \s  #  a whitespace character
 .*  #  and the rest of the line
)+   # once or more