while RUN2:
chose = int(input('Type the option number from 1 to 6:'))
if chose == 1:
print(grossPayMsg())
print("Your gross pay is", grosspay(workhour, hourlywage))
elif chose == 2:
print(withHoldingsMsg())
print("Your withholdings is", withhd(workhour, hourlywage))
elif chose == 3:
print(federalTaxMsg())
print("Your Federal Tax is", fedtax(workhour, hourlywage))
elif chose == 4:
print(marylandTaxMsg())
print("Your Federal Tax is", mdtax(workhour, hourlywage))
elif chose == 5:
print(netPayMsg())
print("Your Federal Tax is", net(workhour, hourlywage))
elif chose == 6:
print ("Thank you for using. Goodbye!")
RUN2 = False
else:
print("/////// Invalid option number ///////")
====================================================================================
Q。如何避免在按enter键而不是按期权号时出现如下错误?我知道有些用户可能会故意或意外地按回车键。。有什么声明可以避免吗?我只学了int(input)或input。。。你知道吗
ValueError:无法将字符串转换为浮点
ValueError:基数为10的int()的文本无效:“”
=============================================
事先非常感谢。。。。你知道吗
您可以通过更改此代码来删除
none
至
可以使用
strng.isnumeric()
函数检查输入的字符串是否为数字。然后转换成float
并存储在workhour
和hourlywage
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