如果索引模数7==0，则从每个块中提取每个字符

Question

好吧，我有一个随机字母和数字的列表，我在任何时期都吐过，所以它看起来像这样

text = "adkisnckindlikenskdihjgkiskdik.adkisnckindlikenskdihjgkiskdik.adkisnckindlikenskdihjgkiskdikadkisnckindlikenskdihjgkiskdi."

lines = text.split(".")
for stingssplit in lines:
        print(stingssplit)

现在我要把它拿出来：

adkisnckindlikenskdihjgkiskdik
adkisnckindlikenskdihjgkiskdik
adkisnckindlikenskdihjgkiskdik
adkisnckindlikenskdihjgkiskdik

如果索引模数7==0，则从每个块中提取每个字符

我不知道该怎么办？你知道吗

Answer 1

请尝试以下操作：

text = "adkisnckindlikenskdihjgkiskdik.adkisnckindlikenskdihjgkiskdik.adkisnckindlikenskdihjgkiskdikadkisnckindlikenskdihjgkiskdi."

chunks = text.split(".")

for chunk in chunks:
    print ''.join([v for i, v in enumerate(chunk) if i % 7 == 0])

输出：

>>> for chunk in chunks:
...     print ''.join([v for i, v in enumerate(chunk) if i % 7 == 0])
...
akeji
akeji
akejiniik

>>>

或一行：

>>> [''.join([v for i, v in enumerate(chunk) if i % 7 == 0]) for chunk in chunks]
['akeji', 'akeji', 'akejiniik', '']

Answer 2

您可以简单地为其编制索引：

"adkisnckindlikenskdihjgkiskdik"[::7]
# 'akeji'                 # gives you characters at positions 0, 7, 14, 21, 28

---

[line[::7] for line in text.split(".")]
# ['akeji', 'akeji', 'akejiniik', '']