没有类似字符的密码迭代？

Question

我正在读这篇thread，它启发我研究如何优化简单生成密码的暴力强制。你知道吗

我的遭遇：

我试图从key=''.join(random.sample(string.uppercase, 7))迭代所有可用的密码组合。如果我读对了文档：key在本例中，不能由两个相似或相等的字母组成。它始终是（在本例中）唯一的7长大写字符串。你知道吗

• 示例：str(key)无法生成：AARGHJU

问题：

如何更改while语句，使其不迭代包含类似字母的字符串？你知道吗

chars = 'ABCDEFGHIJKLMNOPQRSTUVXYZ' # chars to look for
try:
    while 1:
        # Iteration processess of possibel keys
        for length in range(7,8): # only do length of 7
            to_attempt = product(chars, repeat=length)
            for attempt in to_attempt:
                print(''.join(attempt))

except KeyboardInterrupt:
    print "Keybord interrupt, exiting gracefully anyway."
    sys.exit()

产生ex将产生不必要的时间和功率：

AAAFXEL
AAAFXEM
AAAFXEN
AAAFXEO
AAAFXEP
AAAFXEQ
AAAFXER
AAAFXES

Answer 1

对于整个空间的非重复枚举，可能需要itertools.排列. 你知道吗

```python
from itertools import permutations
chars = 'ABCDEFGHIJKLMNOPQRSTUVXYZ' # chars to look for
try:
    while 1:
        # Iterate through possible keys
        for length in range(7,8):
            to_attempt = permutations(chars, length)
            for attempt in to_attempt:
                print(''.join(attempt))

except KeyboardInterrupt:
    print "Keyboard interrupt, exiting gracefully anyway."
    sys.exit()
```