使用pysp从字典映射数据帧中的值

Question

我想知道如何映射数据帧中特定列中的值。

我有一个数据框，看起来像：

df = sc.parallelize([('india','japan'),('usa','uruguay')]).toDF(['col1','col2'])

+-----+-------+
| col1|   col2|
+-----+-------+
|india|  japan|
|  usa|uruguay|
+-----+-------+

我有一本字典，想从中映射值。

dicts = sc.parallelize([('india','ind'), ('usa','us'),('japan','jpn'),('uruguay','urg')])

我想要的输出是：

+-----+-------+--------+--------+
| col1|   col2|col1_map|col2_map|
+-----+-------+--------+--------+
|india|  japan|     ind|     jpn|
|  usa|uruguay|      us|     urg|
+-----+-------+--------+--------+

我试过使用^{}但它不起作用。它投下错误火花-5063。以下是我失败的方法：

def map_val(x):
    return dicts.lookup(x)[0]

myfun = udf(lambda x: map_val(x), StringType())

df = df.withColumn('col1_map', myfun('col1')) # doesn't work
df = df.withColumn('col2_map', myfun('col2')) # doesn't work

Answer 1

udf方式

我建议您将元组列表更改为dict和broadcast在udf中使用

dicts = sc.broadcast(dict([('india','ind'), ('usa','us'),('japan','jpn'),('uruguay','urg')]))

from pyspark.sql import functions as f
from pyspark.sql import types as t
def newCols(x):
    return dicts.value[x]

callnewColsUdf = f.udf(newCols, t.StringType())

df.withColumn('col1_map', callnewColsUdf(f.col('col1')))\
    .withColumn('col2_map', callnewColsUdf(f.col('col2')))\
    .show(truncate=False)

它应该给你

+-----+-------+--------+--------+
|col1 |col2   |col1_map|col2_map|
+-----+-------+--------+--------+
|india|japan  |ind     |jpn     |
|usa  |uruguay|us      |urg     |
+-----+-------+--------+--------+

连接方式（比udf方式慢）

您所要做的就是将dicts rdd也更改为dataframe，并使用两个具有别名的join，如下所示

df = sc.parallelize([('india','japan'),('usa','uruguay')]).toDF(['col1','col2'])

dicts = sc.parallelize([('india','ind'), ('usa','us'),('japan','jpn'),('uruguay','urg')]).toDF(['key', 'value'])

from pyspark.sql import functions as f
df.join(dicts, df['col1'] == dicts['key'], 'inner')\
    .select(f.col('col1'), f.col('col2'), f.col('value').alias('col1_map'))\
    .join(dicts, df['col2'] == dicts['key'], 'inner') \
    .select(f.col('col1'), f.col('col2'), f.col('col1_map'), f.col('value').alias('col2_map'))\
    .show(truncate=False)

结果应该是一样的