擅长:python、mysql、java
<p>马蒂诺贴出的答案是正确的。为了完成并获得我最初寻找的功能,我将sort\u keyriotios更改为以下内容:</p>
<pre><code>def sort_keyratios:
#define rows that have no useful data
skip_list = [16,17,18,28,29,38,39,40,41,46,51,56,61,62,63,69,70,71,92,93,98,99,100]
skipped = 0
# match datacode to row, column and return data in that position of list
for row in range(0,109):
if row in skip_list:
skipped+=11
continue
for col in range(0,12):
if datacode == col+(11*row)-skipped:
return self.data[row][col]
</code></pre>