我有一个问题,分配行动的按钮,我放在一个网格在kivy。任何帮助都将不胜感激。在
我对所有的编码都是新手,但我一直在努力解决这个问题。我试着给按钮指定一个名称,但它不起作用,因为'on'u press'函数对字符串无效,只对按钮有效。有什么方法可以把我的字符串从网格中归类为一个按钮,还是我做错了所有的事情?我想每个按钮执行不同的行动,所以他们不能归类为同一件事。在
这是我的代码:
import kivy
kivy.require('1.10.0')
from kivy.uix.gridlayout import GridLayout
from kivy.app import App
from kivy.core.window import Window
from kivy.uix.button import Button
class MyApp(App):
def build(self):
def callback(instance):
print('The button 1 is being pressed' % instance.text)
# test 1: I dont think this works because it doesn't work with the grid structure but I tried it anyways
# btn1 = Button(background_color=blue, text='a', size_hint_x=None, width=butw)
# test 2: I don't think it works because it is not classified as a button, but a string.
# btn1 = "layout.add_widget(Button(background_color=blue, text='a', size_hint_x=None, width=butw))"
btn1.bind(on_press=callback)
layout = GridLayout(cols=1, rows=28, row_force_default=True, row_default_height=buth)
layout.add_widget(Button(background_color=blue, text='a', size_hint_x=None, width=butw))
layout.add_widget(Button(background_color=blue2, text='b', size_hint_x=None, width=butw))
layout.add_widget(Button(background_color=blue, text='c', size_hint_x=None, width=butw))
# cont.
return layout
MyApp().run()
谢谢,赖安
所以,在第12行,
print('The button 1 is being pressed' % instance.text)
您试图格式化一个字符串,但是没有指定实例文本的位置。否则,我编辑了一点的代码(下次请从示例中删除所有不需要的代码)可以正常工作,当按下“a”按钮时会打印:对其他具有其他功能的按钮执行相同的操作,就完成了。
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