Python线程让每个线程按顺序处理各自的编号

2024-10-16 17:28:58 发布

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我希望第一个线程处理第一个线程,第五个线程和第九个线程,第二个线程将得到第二个第六个十分之一,第三个第七个线程,第十一个线程,第四个线程将处理第八个和第十二个线程。我知道这是一个(4*counter+original)的重复模式,但是当涉及到实际的_线程进程的移动时,我就不知所措了。这是我到目前为止的情况。 如果我错了,他们就告诉我,因为我愿意接受建议。在

编辑-我使用的是python3.3

def calc(threadName):
    testRange = 100
    testNumber = 100
    timesToTest = 25
    testCounter = 0
    if threadName  == 'ThreadOne':
        testNumber = (testNumber)   + 5*(testCounter)
    if threadName == 'ThreadTwo':
        testNumber = (testNumber+1) + 5*(testCounter)
    if threadName == 'ThreadThree':
        testNumber = (testNumber+2) + 5*(testCounter)
    if threadName == 'ThreadFour':
        testNumber = (testNumber+3) + 5*(testCounter)

    while testCounter < timesToTest:
        testCounter +=1
        while testRange >= 0:
            answer = ((testNumber*3) - ((testNumber-1)**2))
            testbool = isprime(answer)
            print('Testing '+str(testNumber)+' on '+str(threadName))
            testNumber +=1
            testRange -= 1
            if testbool:
                list.append((threadName,testNumber,answer))


threadOne = _thread.start_new_thread(calc,('ThreadOne', ))
threadTwo = _thread.start_new_thread(calc,('ThreadTwo', ))
threadThree = _thread.start_new_thread(calc,('ThreadThree', ))
threadFour = _thread.start_new_thread(calc,('ThreadFour', ))

while 1:
    pass

试过这个:

^{pr2}$

Tags: answernewifcalc线程threadstartwhile
1条回答
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1楼 · 发布于 2024-10-16 17:28:58

据我所知,你想要一个由4个工作线程组成的池,公平地对同一个“作业”进行排队 在那4条线之间。在

我会做更多类似的事情:

import threading
import queue

class Worker(threading.Thread):
    def __init__(self, name):
        threading.Thread.__init__(self)
        self.name = name
        self.jobs_queue = queue.Queue()
        self.results_list = list()
    def run(self):
        while True:
            testNumber = self.jobs_queue.get()
            if testNumber == "END":
                return
            # here, do your stuff with 'testNumber'
            # for example, let's multiply it by 2
            answer = testNumber * 2
            # results are appended to a list
            self.results_list.append((self.name,testNumber,answer))
    def calc(self, n):
        self.jobs_queue.put(n)
        if not self.is_alive():
            self.start()
    def get_result(self):
        return self.results_list
    def stop(self):
        # tell the thread to stop,
        # once jobs in queue are done
        self.jobs_queue.put("END")
        self.join()

workers = [Worker('thread 1'), Worker('thread 2'), Worker('thread 3'), Worker('thread 4')]

for n in range(100):
    w = workers[n % 4]
    w.calc(n)

for w in workers:
    w.stop()

for w in workers:
    print(w.get_result())

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