Python NET启动windows应用程序

Question

如何使用python NET启动像记事本这样的windows应用程序？这是我使用python 2.7.13的源代码：

C:\Python27>python.exe
Python 2.7.13 (v2.7.13:a06454b1afa1, Dec 17 2016, 20:42:59) [MSC v.1500 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import clr
>>> import System
>>> type = System.Type.GetTypeFromProgID("Notepad.Application")
>>> System.Activator.CreateInstance(type)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
System.ArgumentNullException: Value cannot be null.
Parameter name: activationContext
   at System.Runtime.Hosting.ApplicationActivator.CreateInstance(ActivationContext activationContext, String[] activationCustomData)
   at System.Runtime.Hosting.ApplicationActivator.CreateInstance(ActivationContext activationContext)
   at System.Activator.CreateInstance(ActivationContext activationContext)

Answer 1

没有ProgID=“记事本.应用程序“在我的计算机上，pythonnet与其他COM对象一起工作：

>>> import clr
>>> import System
>>> type1=System.Type.GetTypeFromProgID("Excel.Application")
>>> type1
<System.RuntimeType object at 0x02ABEE10>
>>> System.Activator.CreateInstance(type1)
<Microsoft.Office.Interop.Excel.ApplicationClass object at 0x02AD11D0>