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<p><strong>我的问题</strong></p>
<p>我们将这个数组类型的数据称为m:</p>
<pre><code> 0 1 2 3
0 746200.0 IP:aWSrjjB foldcauchy foldcauchy(c=3.40, loc=853.32, scale=188436.01)
1 1061881.5 IP:joW6uH4 johnsonsu johnsonsu(a=-0.39, b=0.46, loc=715076.10, scale=70401.41)
2 645000.0 IP:4Q3L2kB foldcauchy foldcauchy(c=3.94, loc=835.77, scale=184545.16)
3 284375.0 IP:WLP1cdn loglaplace loglaplace(c=1.81, loc=-1001.33, scale=701001.33)
4 666600.0 IP:kQn348T johnsonsu johnsonsu(a=-0.39, b=0.46, loc=715076.10, scale=70401.41)
5 754678.5 IP:kQn348T loglaplace loglaplace(c=1.93, loc=-1087.33, scale=786087.33)
</code></pre>
<p>第二列是每行的唯一IP。它的类型是str</p>
<p>最后一列是每行的一组分布。它的类型是str</p>
<p>我想将唯一的IP附加到最后一列。在</p>
<hr/>
<p><strong>我的尝试</strong></p>
<p>我尝试使用以下代码:</p>
^{pr2}$
<p>然而,这导致了错误的输出:</p>
<pre><code> ['loglaplace(c=1.88, loc=-932.82, scale=674382.82)',
'IP:slaL5jw']
</code></pre>
<p>虽然我可以使用<code>str( ['loglaplace(c=1.88, loc=-932.82, scale=674382.82)',
'IP:slaL5jw'])</code></p>
<hr/>
<p><strong>所需输出示例:</strong></p>
<pre><code> 0 1 2 3
0 746200.0 IP:aWSrjjB foldcauchy foldcauchy(c=3.40, loc=853.32, scale=188436.01, IP:aWSrjjB)
1 1061881.5 IP:joW6uH4 johnsonsu johnsonsu(a=-0.39, b=0.46, loc=715076.10, scale=70401.41, IP:joW6uH4)
</code></pre>