列表Python的随机输出

Question

Stores = ["alpha","bravo","charlie","delta"]
KnownName = Stores.pop()
KnownName2 = Stores.pop()
KnownName3 = Stores.pop()
print KnownName+" "+Stores.pop() 
print KnownName2+" "+KnownName
print KnownName3+" "+KnownName2 
print KnownName3 

输出：

^{pr2}$

如果我有m1，m2，m3…mn的列表 我正试着像这样胡乱乱搞

m1
m2 m3
m4 m2
m5
m6 m7
m8 m9
m10 m8
m11 m10

如果你看输出，一行最多有两个值。只有第一个值可以重复。在

如何改进我的代码？在

foo = ['m1', 'm2', 'm3', 'm4', 'm5','m6','m7','m8']
foo.reverse()
while foo:
    try:
        if random.randrange(0,2) == 0:
            print foo.pop()
        else:
            Value2 = foo.pop()
            print Value2 + " " + foo.pop()
            if random.randrange(0,2) == 0:
                Value3 = foo.pop()
                print Value3 + " " + Value2
            else:
                foo.pop() + foo.pop()
    except:
        break

Answer 1

你可以试试这个。在

from random import randint

foo = ['m1', 'm2', 'm3', 'm4', 'm5','m6','m7','m8']
while foo:
    x = randint(0, len(foo) - 1)
    y = randint(0, len(foo) - 1)
    while x == y and len(foo) > 1:
        y = randint(0, len(foo) - 1)
    if randint(0, 1) == 0 or len(foo) <= 1:
        print foo[x]
    else:
        print foo[y], foo[x]
    foo = foo[:x] + foo[x+1:]