d = [{'A': ['B', 'C', 'D']}, {'B': ['E', 'F']}, {'C': ['E']}, {'F': ['G', 'H']}]
d1 = dict(list(i.items())[0] for i in d)
def flatten_structure(d, root = 'A'):
if root:
return {root:flatten_structure(d1[root], None)}
return {i:flatten_structure(d1[i], None) if i in d1 else None for i in d}
print(flatten_structure(d1['A']))
def find_set(d, k, v):
for key, value in d.items():
if isinstance(value, dict):
find_set(d[key], k, v)
return
if key == k:
d[key] = {}
for i in v:
d[key][i] = None
return d
d[k] = {}
for i in v:
d[k][i] = None
return d
您可以使用递归:
输出:
^{pr2}$可以使用递归函数执行此操作:
代码:
^{pr2}$d
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