擅长:python、mysql、java
<pre><code># menu=('Veg Roll','Noodles','Fried Rice','Soup')
# quantity_available=[2,200,250,3]
menudict={"Veg Roll":2,"Noodles":200,'Fried Rice':250,'Soup':3}
def place_order(*kwargs):
countt=len(kwargs)
for i in range(0,countt,2):
if(not menudict.keys().__contains__(kwargs[i])):
print("Item "+kwargs[i]+" is not available")
elif(menudict[kwargs[i]]<kwargs[i+1]):
print(kwargs[i] + " stock is over")
else:
menudict[kwargs[i]]-=kwargs[i+1]
print(kwargs[i]+" is available")
# def check_quantity_available(index,quantity_requested):
# pass
place_order("Veg Roll",2,"Noodles",2)
place_order("Soup",1,"Veg Roll", 2, "Fried Rice1",1)
</code></pre>
<blockquote>
<p>USING DICTIONARY MAKES IT VERY EASY.</p>
</blockquote>