数据CSV仪表板python

Question

在这个foro的帮助下，我可以创建我的Optimizator仪表板。现在，我需要做些改变。代码如下：

import csv
import datetime

with open("prueba.csv", 'rb') as f:
    reader = csv.reader(f)
    your_list = list(reader)



mydict = {}
for row in your_list[1:]:
    date = datetime.datetime.strptime(row[0],'%d/%m/%Y')
    name = row[1]
    mydict[(date,name)] = row[2:]


def convert(n):
    n = n.replace(",",".").replace("%","")
    try:
        return float(n)
    except ValueError:
        return 0e0


for (day, name) in mydict:
    previous_day = day - datetime.timedelta(days=1)
    if (previous_day,name) in mydict:
        print name, datetime.datetime.strftime(day,"%d/%m/%Y")
        day2_values = mydict[(day, name)]
        day1_values = mydict[(previous_day, name)]
        comparer = zip(day2_values, day1_values)
        for n,value in enumerate(comparer):
            print "item[%d]:" % (n+2,),
            if convert(value[1]) < convert(value[0]):
                print value[1], "smaller than", value[0], "Incremento"
            else:
                print value[1], "bigger than", value[0], "Descenso"
        print

>>>
Martin 18/12/2017
item[2]: 312341 smaller than 349805 Incremento
item[3]: 45368 smaller than 46818 Incremento
item[4]: 14.53% bigger than 13.38% Bajada
item[5]: 39.35 bigger than 32.98 Bajada
item[6]: 0.87 bigger than 0.70 Bajada

Jose 11 03/12/2017
item[2]: 140580 smaller than 161540 Incremento
item[3]: 4943 bigger than 4663 Bajada
item[4]: 3.52% bigger than 2.89% Bajada
item[5]: 2.04 bigger than 1.95 Bajada
item[6]: 0.41 smaller than 0.42 Incremento

Jorge cl 17/12/2017
item[2]: 156736 smaller than 164272 Incremento
item[3]: 39295 bigger than 36921 Bajada
item[4]: 25.07% bigger than 22.48% Bajada
item[5]: 19.74 bigger than 19.61 Bajada
item[6]: 0.50 smaller than 0.53 Incremento

我需要更改实名的返回值items[2],items[3],items[4],items[5] and items[6]：[['"Fecha"', '"Cliente"', '"Subastas"', '"Impresiones_exchange"', '"Fill_rate"', '"Importe_a_pagar_a_medio"', '"ECPM_medio"']

另外，我需要按客户名称以csv文件顺序保存返回。有可能吗？？在

Answer 1

实名在your_list[0]。所以改变这条线

print "item[%d]:" % (n+2,),

为此：

^{pr2}$

要将输出保存为csv，而不是（或同时）打印数据，您需要保存它，以便将其传递给csv.writer。创建一个名为result的列表，对于要在输出中看到的每一行，请执行以下操作：

row = [name, datetime.datetime.strftime(day,"%d/%m/%Y"), mylist[0][n+2],value[1], value[0]]
result.append(row)

完成生成result后，按名称对其进行排序：

result.sort()

使用csv.writer()从该列表生成csv文件，对result中的每一行调用writer对象的writerow()方法。在