因此,目前我的凯撒密码程序运行良好,每当我使用小写字母。我希望它工作时,我输入一个单词或短语与大写。这就是我现在的密码。希望你们能帮我完成这件事。在
def encrypt(消息,距离): “”“将获取邮件并将其旋转一段距离,以便创建加密邮件”“”
encryption = ""
for ch in message:
ordvalue = ord(ch)
cipherValue = ordvalue + distance
if cipherValue > ord("z"):
cipherValue = ord("a") + distance - (ord("z") - ordvalue + 1)
encryption += chr(cipherValue)
return encryption
def decrypt(消息,距离): “”“将解密上述邮件”“”
^{pr2}$def二进制转换(消息): “”“将把单词转换成二进制代码”“”
binary = ""
for cb in message:
binaryString = " " #Binary number
binaryNumber = ord(cb)
while binaryNumber > 0:
binaryRemainder = binaryNumber % 2
binaryNumber = binaryNumber // 2
binaryString = str(binaryRemainder) + binaryString
binary += binaryString
return binary
运行=真
运行时:
#input
message = input("Enter word to be encrypted: ") #original message
distance = int(input("Enter the distance value: ")) #distance letters will be moved
#variables
fancy = encrypt(message, distance)
boring = decrypt(fancy, distance)
numbers = binaryConversion(message)
#output
print("\n")
print("Your word was: ", format(message, ">20s"))
print("The distance you rotated was: ", format(distance), "\n")
print("The encryption is: ", format(fancy, ">16s"))
print("The decryption is: ", format(boring, ">16s"))
print("The binary code is: ", format(numbers)) #I know an error comes here but it will work in the end
repeat = input("Would you like to encrypt again? Y/N ")
print("\n")
if repeat == "N" or repeat == "n":
run = False
else:
run = True
print(“谢谢你&就像朱利叶斯·凯撒曾经说过的‘威尼斯,维迪,维西’”)
谢谢你
我建议你用一种映射的心态来解决这个问题,而不是一种补偿。您可以基于偏移量构建映射,但如果使用字典或其他形式的一对一映射,则字符处理会更容易。在
例如:
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