我对python还不熟悉,但我希望有更多经验的人能帮助我。
我正在尝试编写一个python脚本:
这个问题涉及到两个数据结构点和矩形类。我已经开始创建点类和矩形类。矩形类应该保存从随机模块的随机方法创建的相关数据集。你可以从我的尝试中看出,我已经到处都是了,但我已经用评论来试图得到我想要做的。
我的具体问题是:
1) 我怎样才能让这个脚本工作?
2) 我缺少哪些变量或函数来生成随机矩形并查看这些矩形中是否有特定点?
## 1. Declare the Point class
class Point:
def __init__(self,x = 0.0, y = 0.0):
self.x = x
self.y = y
pass
## 2. Declare the Rectangle class
class Rectangle:
def __int__(self): ## A rectangle can be determined aby (minX, maxX) (minY, maxY)
self.minX = self.minY = 0.0
self.maxX = self.maxY = 1.0
def contains(self, point): ## add code to check if a point is within a rectangle
"""Return true if a point is inside the rectangle."""
# Determine if a point is inside a given polygon or not
# Polygon is a list of (x,y) pairs. This function
# returns True or False.
def point_in_poly(x,y,poly):
n = len(poly)
inside = False
p1x,p1y = poly[0]
for i in range(n+1):
p2x,p2y = poly[i % n]
if y > min(p1y,p2y):
if y <= max(p1y,p2y):
if x <= max(p1x,p2x):
if p1y != p2y:
xints = (y-p1y)*(p2x-p1x)/(p2y-p1y)+p1x
if p1x == p2x or x <= xints:
inside = not inside
p1x,p1y = p2x,p2y
return inside
## 3. Generate four points
##define a Point list to keep four points
points = []
##add codes to generate four points and append to the points list
polygon = [(0,10),(10,10),(10,0),(0,0)]
point_x = 5
point_y = 5
## 4. Generate four rectangles
##define a Rectangle list
rects = []
for i in range(4):
rectangle = Rectangle()
## Generate x
x1 = random.random()
x2 = random.random()
## make sure minX != maxX
while(x1 == x2):
x1 = random.random()
if x1<x2:
rectangle.minX=x1
rectangle.maxX=x2
elif x1>x2:
rectangle.minX=x2
rectangle.maxX=x1
rects.append(rectangle)
## Develop codes to generate y values below
## make sure minY != maxY
while(y1 == y2):
y1 = random.random()
if y1<y2:
rectangle.minY=y1
rectangle.maxY=y2
elif y1>y2:
recetangle.minY=y2
racetangle.maxY=y1
## add to the list
rects.append(rectangle)
## 5. Add code to check which point is in which rectangle
resultList = [] ## And use a list to keep the results
for i in range(4):
for j in range(4):
if points[i] in rectangle[j]:
print i
# write the results to file
f=open('Code5_4_1_Results.txt','w')
for result in resultList:
f.write(result+'\n')
f.close()
这是非常简单的数学。给定一个有点(x1,y1)和(x2,y2)的矩形,并假设
x1 < x2
和y1 < y2
(如果不是,您可以交换它们),如果x1 < x < x2 and y1 < y < y2
,则点(x,y)在该矩形内。由于Python比较运算符可以被链接,这甚至是有效的Python代码,它应该产生正确的结果(在其他语言中,您必须编写x1 < x and x < x2
等)。如果需要,可以使用
<=
,而不是<
。使用<=
表示矩形边界上的点(例如,点(x1,y1))计为位于矩形内,而使用<
则表示此类点位于矩形外。相关问题 更多 >
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